Aptitude Percentage Online Test, Free Aptitude Quiz
Quizsummary
0 of 15 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
Information
Aptitude Percentage Online Test, Free Aptitude Quiz, Online Aptitude Percentage Test. Aptitude Percentage Question and Answers 2017. Aptitude Percentage Quiz. Aptitude Percentage Free Mock Test 2017. Aptitude Percentage Question and Answers in PDF. The Aptitude Percentage online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Percentage Question and Answers in Hindi and English. Aptitude Percentage Mock test for topic via Online Mode. Here we are providing Aptitude Percentage Mock Test in Hindi. Now Test your self for “Aptitude Percentage Online Test in Hindi” Exam by using below quiz…
This paper has 15 questions.
Time allowed is 20 minutes.
The Aptitude Percentage online Mock Test is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 15 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Average score 

Your score 

Categories
 Not categorized 0%
Pos.  Name  Entered on  Points  Result 

Table is loading  
No data available  
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 Answered
 Review

Question 1 of 15
1. Question
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Correct
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 110 – (60)
= 50.
Required percentage = (50/110 × 100)% =Incorrect
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 110 – (60)
= 50.
Required percentage = (50/110 × 100)% = 
Question 2 of 15
2. Question
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Correct
Let their marks be (x + 9) and x.
Then, x + 9 = 56/100 (x + 9 + x)
⇒ 25(x + 9) = 14(2x + 9)
⇒ 3x = 99
⇒ x = 33
So, their marks are 42 and 33.Incorrect
Let their marks be (x + 9) and x.
Then, x + 9 = 56/100 (x + 9 + x)
⇒ 25(x + 9) = 14(2x + 9)
⇒ 3x = 99
⇒ x = 33
So, their marks are 42 and 33. 
Question 3 of 15
3. Question
A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:
Correct
Suppose originally he had x apples.
Then, (100 – 40)% of x = 420.
⇒ 60/100 x x = 420
⇒ x = 420×100 / 60) = 700.Incorrect
Suppose originally he had x apples.
Then, (100 – 40)% of x = 420.
⇒ 60/100 x x = 420
⇒ x = 420×100 / 60) = 700. 
Question 4 of 15
4. Question
What percentage of numbers from 1 to 70 have 1 or 9 in the unit’s digit?
Correct
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number = 14
Required percentage = (14/70 × 100)% = 20%.Incorrect
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number = 14
Required percentage = (14/70 × 100)% = 20%. 
Question 5 of 15
5. Question
If A = x% of y and B = y% of x, then which of the following is true?
Correct
x% of y = (x/100 × y) = (y/100 × x) = y% of x
∴ A = B.Incorrect
x% of y = (x/100 × y) = (y/100 × x) = y% of x
∴ A = B. 
Question 6 of 15
6. Question
If 20% of a = b, then b% of 20 is the same as:
Correct
20% of a = b ⇒ 20/100 a = b.
b% of 20 = (b/100 × 20) = (20/100 a × 1/100 × 20) = 4/100 a = 4% of a.Incorrect
20% of a = b ⇒ 20/100 a = b.
b% of 20 = (b/100 × 20) = (20/100 a × 1/100 × 20) = 4/100 a = 4% of a. 
Question 7 of 15
7. Question
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Correct
Let the number of students be x. Then,
Number of students above 8 years of age = (100 – 20)% of x = 80% of x.
∴ 80% of x = 48 + 2/3 of 48
⇒ 80/100 x = 80
⇒ x = 100.Incorrect
Let the number of students be x. Then,
Number of students above 8 years of age = (100 – 20)% of x = 80% of x.
∴ 80% of x = 48 + 2/3 of 48
⇒ 80/100 x = 80
⇒ x = 100. 
Question 8 of 15
8. Question
Two numbers A and B are such that the sum of 5% of A and 4% of B is twothird of the sum of 6% of A and 8% of B. Find the ratio of A : B.
Correct
Incorrect

Question 9 of 15
9. Question
A student multiplied a number by 3/5 instead of 5/3 .
What is the percentage error in the calculation?Correct
Let the number be x.
Then, error = 5/3 x – 3/5 x = 16/15 x
Error% = 16x/15 × 3/5x × 100)% = 64%Incorrect
Let the number be x.
Then, error = 5/3 x – 3/5 x = 16/15 x
Error% = 16x/15 × 3/5x × 100)% = 64% 
Question 10 of 15
10. Question
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
Correct
Number of valid votes = 80% of 7500 = 6000.
∴ Valid votes polled by other candidate = 45% of 6000
= (45/100 x 6000) = 2700.Incorrect
Number of valid votes = 80% of 7500 = 6000.
∴ Valid votes polled by other candidate = 45% of 6000
= (45/100 x 6000) = 2700. 
Question 11 of 15
11. Question
Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
Correct
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
Required percentage = (11628/20400 × 100)% = 57%Incorrect
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
Required percentage = (11628/20400 × 100)% = 57% 
Question 12 of 15
12. Question
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Correct
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
⇒ z + 120/100 z = 550
⇒ 11/5 z = 550
⇒ z = (550 × 5/11) = 250.Incorrect
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
⇒ z + 120/100 z = 550
⇒ 11/5 z = 550
⇒ z = (550 × 5/11) = 250. 
Question 13 of 15
13. Question
Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Correct
Let the amount taxable purchases be Rs. x.
Then, 6% of x = 30/100
x = (30/100 × 100/6) = 5.
∴ Cost of tax free items = Rs. [25 – (5 + 0.30)] = Rs. 19.70Incorrect
Let the amount taxable purchases be Rs. x.
Then, 6% of x = 30/100
x = (30/100 × 100/6) = 5.
∴ Cost of tax free items = Rs. [25 – (5 + 0.30)] = Rs. 19.70 
Question 14 of 15
14. Question
Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods.
Correct
Rebate = 6% of Rs. 6650 = Rs. (6/100 x 6650) = Rs. 399.
Sales tax = 10% of Rs. (6650 – 399) = Rs. (10/100 x 6251) = Rs. 625.10
∴ Final amount = Rs. (6251 + 625.10) = Rs. 6876.10Incorrect
Rebate = 6% of Rs. 6650 = Rs. (6/100 x 6650) = Rs. 399.
Sales tax = 10% of Rs. (6650 – 399) = Rs. (10/100 x 6251) = Rs. 625.10
∴ Final amount = Rs. (6251 + 625.10) = Rs. 6876.10 
Question 15 of 15
15. Question
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Correct
Increase in 10 years = (262500 – 175000) = 87500.
Increase% = (87500/175000) x 100 % = 50%.
Required average = (50/10) % = 5%.Incorrect
Increase in 10 years = (262500 – 175000) = 87500.
Increase% = (87500/175000) x 100 % = 50%.
Required average = (50/10) % = 5%.