JEE Main Chemistry Electrochemistry Online Test
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JEE Main Chemistry Electrochemistry Online Test. JEE Main Online Test for Chemistry Electrochemistry. JEE Main Full Online Quiz for Chemistry Electrochemistry. JEE Main Free Mock Test Paper 2024. JEE Main 2024 Free Online Practice Test, Take JEE Online Test for All Subjects. JEE Main Question and Answers for Chemistry Electrochemistry. In this test You may find JEE Main all subjects Questions with Answers. Check JEE Main Question and Answers in English. This mock Test is free for All Students. Mock Test Papers are very helpful for Exam Purpose, by using below Mock Test Paper you may Test your Study for Next Upcoming Exams. Now Scroll down below n Take JEE Main Chemistry Electrochemistry…
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Question 1 of 30
1. Question
The cell constant of a conductivity cell ………… .
Correct
Incorrect
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Question 2 of 30
2. Question
Electrolysis, involves oxidation and reduction respectively at
Correct
Incorrect
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Question 3 of 30
3. Question
The quantity of charge required to obtain one mole of aluminium from Al2O3 is
Correct
Incorrect
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Question 4 of 30
4. Question
The standard oxidation potentials for Mn3+ ion acid solution are MnO2. Is the reaction 2MN3+ + 2H2O → Mn2+ + MnO2 + 4H+ spontaneous under conditions of unit activity? What is the change in free energy?
Correct
∆G = ∆G° + 2.303 RT log Q
Q = 1 (activity = 1)
∆G = ∆G°
Mn+3 + e– → Mn+2 ∆G° = – 1 × F × 1.5
Mn+3 + 2H2O → MnO2 + 4H+ + e– ∆G°2 = – 1 × F × (–1)
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2Mn3+ + 2H2O → Mn2+ + MnO2 + 4 H+ ∆G° = ∆G°1 + ∆G°2 = – 48250 J (∆G < 0)
Incorrect
∆G = ∆G° + 2.303 RT log Q
Q = 1 (activity = 1)
∆G = ∆G°
Mn+3 + e– → Mn+2 ∆G° = – 1 × F × 1.5
Mn+3 + 2H2O → MnO2 + 4H+ + e– ∆G°2 = – 1 × F × (–1)
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2Mn3+ + 2H2O → Mn2+ + MnO2 + 4 H+ ∆G° = ∆G°1 + ∆G°2 = – 48250 J (∆G < 0)
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Question 5 of 30
5. Question
The platinum electrodes were immersed in a solution of cupric sulphate and electric current was passed through the solution. After sometimes, it was found that color of copper sulphate disappeared with evolution of gas at the electrode. The colorless solution contains
Correct
During electrolysis of CuSO4, Cu2+ gets discharged at cathode and OH– at anode. Thus, solution becomes acidic due to excess of H+ and SO42– or H2SO4 (sulphuric acid).
Incorrect
During electrolysis of CuSO4, Cu2+ gets discharged at cathode and OH– at anode. Thus, solution becomes acidic due to excess of H+ and SO42– or H2SO4 (sulphuric acid).
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Question 6 of 30
6. Question
In the galvanic cell,
Fe(s) + 2Fe3+(aq) → 3Fe2+ (aq)
Correct
Incorrect
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Question 7 of 30
7. Question
If a salt bridge is removed from the two half cells, the voltage
Correct
When the salt bridge is removed, potential drops to zero.
Incorrect
When the salt bridge is removed, potential drops to zero.
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Question 8 of 30
8. Question
In anodizing
Correct
Incorrect
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Question 9 of 30
9. Question
When a lead storage battery is charged, it acts as
Correct
Incorrect
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Question 10 of 30
10. Question
Al3+ (aq) + 3e– → Al(s); E° = – 1.66 V
Cu2+ (aq) + 2e– → Cu(s); E° = + 0.34 V
What voltage is produced under standard conditions to give a spontaneous reactions by combination of these two half-cells?
Correct
Reducing power of Al is larger than that of Cu.
Incorrect
Reducing power of Al is larger than that of Cu.
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Question 11 of 30
11. Question
A solution of sodium sulphate in water is electrolyzed using inert electrodes. The products at the cathode and anode are respectively
Correct
At cathode 2 H+ + 2 e– → H2
At anode 2OH– → H2O + 1/2 O2 + 2 e–
Incorrect
At cathode 2 H+ + 2 e– → H2
At anode 2OH– → H2O + 1/2 O2 + 2 e–
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Question 12 of 30
12. Question
Consider the following sets
Blue color solution changes to colorless (or fades) in
Correct
Incorrect
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Question 13 of 30
13. Question
If the DG of a cell reaction AgCl + e– → Ag + Cl– is – 21.20 kJ, the standard emf of cell is
Correct
We know that, ∆G° = – nFE°
– 21.2 × 103 = – 1 × 96500 × E°
E° = 21.2 × 103/96500
E° = 0.220 V
Incorrect
We know that, ∆G° = – nFE°
– 21.2 × 103 = – 1 × 96500 × E°
E° = 21.2 × 103/96500
E° = 0.220 V
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Question 14 of 30
14. Question
Consider the half-cell reactions,
H2O2 → O2 + 2H+ + 2e– E° = – 0.69 V
H2O2 + 2H+ + 2e– → 2H2O E° = 1.77 V
Fe2+ → Fe3+ + e– E° = 0.771 V
Fe → Fe2+ + 2e– E° = 0.44 V
If H2O2 is mixed with Fe2+, which reaction is more likely?
Correct
H2O2 + 2H+ + 2Fe2+ → 2Fe3+ + 2H2O
E0cell = 1.77 + 0.771 = 2.541 V
Incorrect
H2O2 + 2H+ + 2Fe2+ → 2Fe3+ + 2H2O
E0cell = 1.77 + 0.771 = 2.541 V
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Question 15 of 30
15. Question
Aqueous solution of NaCl containing a small amount of MeOH (methyl orange) is electrolyzed using Pt-electrodes. The color of the solution after some time will:
Correct
Remains yellow since solution is basic after electrolysis & MeOH shows red color in acidic medium.
Incorrect
Remains yellow since solution is basic after electrolysis & MeOH shows red color in acidic medium.
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Question 16 of 30
16. Question
In a galvanic cell, the electrons flow from
Correct
Incorrect
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Question 17 of 30
17. Question
For the electrochemical cell,
H2(g) 1 atm | H+ (1 M) || Cu2+ (1 M) | Cu(s)
Which one of the following statements is true?
Correct
H2 is anode because oxidation takes place. Cu is cathode because reduction takes place.
Incorrect
H2 is anode because oxidation takes place. Cu is cathode because reduction takes place.
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Question 18 of 30
18. Question
When a dilute aqueous Li2SO4 solution is electrolyzed, the products formed at the anode and cathode, respectively, are
Correct
Incorrect
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Question 19 of 30
19. Question
Using the standard electrode potential values given below, decide which of the statements, I, II, III and IV are correct. Choose the right answer from (A) (B) (C) and (D)
Fe2+ + 2e– ⇌ Fe ; E0 = – 0.44 V
Cu2+ + 2e– ⇌ Cu ; E0 = + 0.34 V
Ag+ + e– ⇌ Fe ; E0 = + 0.80 V
I. Copper can displace iron from FeSO4 solution.
II. Iron can displace copper from CuSO4 solution
III. Silver can displace copper from CuSO4 solution
IV. Iron can displace silver from AgNO3 solution
Correct
Incorrect
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Question 20 of 30
20. Question
The standard electrode potential for the following reaction is + 1.33 V. What is the potential at pH = 2.0?
Cr2O72– (aq, 1M) + 14 H+ (aq) + 6e– → 2Cr3+ (aq. 1 M) + 7H2O (l)
Correct
Incorrect
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Question 21 of 30
21. Question
A gas X at 1 atm is bubbled through a solution containing a mixture of 1 M y– and 1 M z– at 250C. If the order of reduction potential is z > y > x then
Correct
Since the order of reduction potential is z > y > x
So z can oxidize x as well as y.
Y can oxidize x but not z
X can reduce z as well as y.
Incorrect
Since the order of reduction potential is z > y > x
So z can oxidize x as well as y.
Y can oxidize x but not z
X can reduce z as well as y.
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Question 22 of 30
22. Question
1 Faraday of electricity is passed through the solutions containing 1mole each of CuSO4, AlCl3 and SiCl4. Number of moles of Cu, Al and Si formed will be in the ratio
Correct
Reaction Number of moles formed by 1F
Cu2+ + 2e– → Cu 1/2
Al3+ + 3e– → Al 1/3
Si4+ + 4e– → Si 1/4
Ratio 1/2, 1/3, 1/4
= 6 : 4 : 3
Incorrect
Reaction Number of moles formed by 1F
Cu2+ + 2e– → Cu 1/2
Al3+ + 3e– → Al 1/3
Si4+ + 4e– → Si 1/4
Ratio 1/2, 1/3, 1/4
= 6 : 4 : 3
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Question 23 of 30
23. Question
1 mole of electrons passes through each of the solution of AgNO3, CuSO4 and AlCl3 when Ag, Cu and Al are deposited. Their molar ratio will be
Correct
Ag+ + e– → Ag
Cu2+ + 2e– → Cu
Al3+ + 3e– → Al
Ag formed = 1 mol
Cu formed = 1/2 mol
Al formed = 1/2 mol
Incorrect
Ag+ + e– → Ag
Cu2+ + 2e– → Cu
Al3+ + 3e– → Al
Ag formed = 1 mol
Cu formed = 1/2 mol
Al formed = 1/2 mol
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Question 24 of 30
24. Question
The limiting equivalent conductivity of NaCl, KCl and KBr are 126.5, 150.0 and 151.5 S cm2 eq–1, respectively the limiting equivalent ionic conductance for Br– is 78 S cm2 eq–1. The limiting equivalent ionic conductance for Na+ ions would be:
Correct
∧∞m (NaBr) = ∧∞m (NaCl) + ∧∞m (KBr) – ∧∞m (KCl)
∧∞m (Na+) + ∧∞m (Br–) = 126.5 + 151.5 – 150
∧∞m (Na+) = 50
Incorrect
∧∞m (NaBr) = ∧∞m (NaCl) + ∧∞m (KBr) – ∧∞m (KCl)
∧∞m (Na+) + ∧∞m (Br–) = 126.5 + 151.5 – 150
∧∞m (Na+) = 50
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Question 25 of 30
25. Question
On passing 1 F of electricity through the electrolytic cells containing Ag+, Ni2+ and Cr3+ ions solution, the deposited Ag(at. Wt. = 108), Ni (at. Wt. = 59) and Cr (at. wt. = 52) is
Correct
Weight of Ag deposited = eq. wt. of Ag = 108 g
Weight of Ni deposited = eq. wt. of Ni = 29.5 g
Weight of Cr deposited = eq. wt. of Cr = 17.3 g
Incorrect
Weight of Ag deposited = eq. wt. of Ag = 108 g
Weight of Ni deposited = eq. wt. of Ni = 29.5 g
Weight of Cr deposited = eq. wt. of Cr = 17.3 g
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Question 26 of 30
26. Question
Which of the following statements is true for fuel cells?
Correct
Incorrect
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Question 27 of 30
27. Question
Debye Huckel theory predicts
Correct
Incorrect
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Question 28 of 30
28. Question
The equivalent conductance of Ba2+ and Cl– are respectively 127 and 76Ω–1 cm2 equiv–1 at infinite dilution. The equivalent conductance (in Ω–1 cm2 equiv–1) of BaCl2 at infinite dilution will be
Correct
Incorrect
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Question 29 of 30
29. Question
The standard potential at 25°C for the following half–reactions are given against them
Zn2+ + 2e– → Zn; E° = – 0.762 V
Mg2+ + 2e– → Mg; E° = – 2.37 V
When zinc dust is added to the solution of MgCl2,
Correct
Zn + MgCl2 → no reaction
This type of reaction does not occur because
Mg2+ E° = – 2.37 V, while Zn2+ E° = – 0.76 V
Incorrect
Zn + MgCl2 → no reaction
This type of reaction does not occur because
Mg2+ E° = – 2.37 V, while Zn2+ E° = – 0.76 V
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Question 30 of 30
30. Question
In Hall process, in the production of Al, carbon is used as the anode material. The reaction are
Correct
Incorrect