SEBI Online Test in English Series 3, SEBI Online Mock Test 3
Finish Quiz
0 of 50 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
Information
SEBI Online Test in English Series 3, SEBI Online Mock Test 3, SEBI Free Online Test Series 3. RRB Exam Online Test 2024, SEBI Free Mock Test Exam 2024. SEBI Exam Free Online Quiz 2024, SEBI Full Online Mock Test Series 3rd in English. RRB Online Test for All Subjects, SEBI Free Mock Test Series in English. SEBI Free Mock Test Series 3. SEBI English Language Online Test in English Series 3rd. SEBI Quantitative Aptitude Quiz 2024, SEBI Reasoning Ability Free Online Test. Take SEBI Online Quiz. The SEBI Full online mock test paper is free for all students. SEBI Question and Answers in English and Hindi Series 3. Here we are providing SEBI Full Mock Test Paper in English. SEBI Mock Test Series 3rd 2024. Now Test your self for SEBI Exam by using below quiz…
This paper has 50 questions.
Time allowed is 50 minutes.
The SEBI Online Test Series 3rd, SEBI Free Online Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 50 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
| Average score |
|
| Your score |
|
Categories
- Not categorized 0%
| Pos. | Name | Entered on | Points | Result |
|---|---|---|---|---|
| Table is loading | ||||
| No data available | ||||
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
- Answered
- Review
-
Question 1 of 50
1. Question
In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Correct
Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec.Incorrect
Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec. -
Question 2 of 50
2. Question
A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?
Correct
3 — 1725
5 — 1875
————–
2 — 150
N = 1 I = 75 R = ?
P = 1725 – 225 = 1500
75 = (1500*1*R)/100
R = 5%Incorrect
3 — 1725
5 — 1875
————–
2 — 150
N = 1 I = 75 R = ?
P = 1725 – 225 = 1500
75 = (1500*1*R)/100
R = 5% -
Question 3 of 50
3. Question
Find the area of a parallelogram with base 24 cm and height 16 cm.
Correct
Area of a parallelogram = base * height = 24 * 16 = 384 cm2
Incorrect
Area of a parallelogram = base * height = 24 * 16 = 384 cm2
-
Question 4 of 50
4. Question
Twelve men and six women together can complete a piece of work in four days. The work done by a women in one day is half the work done by a man in one day. If 12 men and six women started working and after two days, six men left and six women joined, then in hoe many more days will the work be completed?
Correct
Work done by a women in one day = 1/2 (work done by a man/day)
One women’s capacity = 1/2(one man’s capacity)
One man = 2 women.
12 men = 24 women.
12 men + 6 women = 30 women
30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.
Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days.Incorrect
Work done by a women in one day = 1/2 (work done by a man/day)
One women’s capacity = 1/2(one man’s capacity)
One man = 2 women.
12 men = 24 women.
12 men + 6 women = 30 women
30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.
Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days. -
Question 5 of 50
5. Question
Find the one which does not belong to that group ?
Correct
3, 5, 9 and 7 are odd numbers, but not 4.
Incorrect
3, 5, 9 and 7 are odd numbers, but not 4.
-
Question 6 of 50
6. Question
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in?
Correct
(A + B + C)’s 1 day work = 1/6;
(A + B)’s 1 day work = 1/8
(B + C)’s 1 day work = 1/12
(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)
= (1/3 – 5/24) = 1/8
So, A and C together will do the work in 8 days.Incorrect
(A + B + C)’s 1 day work = 1/6;
(A + B)’s 1 day work = 1/8
(B + C)’s 1 day work = 1/12
(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)
= (1/3 – 5/24) = 1/8
So, A and C together will do the work in 8 days. -
Question 7 of 50
7. Question
What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high?
Correct
d2 = 122 + 42 + 32 = 13
Incorrect
d2 = 122 + 42 + 32 = 13
-
Question 8 of 50
8. Question
7394 – 1236 – 4652 = ?
Correct
Incorrect
-
Question 9 of 50
9. Question
The average salary per head of the entire staff of an office including the officers and clerks is Rs.90. The average salary of officers is Rs.600 and that of the clerks is Rs.84. If the number of officers is 2, find the number of officers in the office?
Correct
Incorrect
-
Question 10 of 50
10. Question
Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.
Correct
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.Incorrect
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours. -
Question 11 of 50
11. Question
If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :
Correct
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22Incorrect
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22 -
Question 12 of 50
12. Question
A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?
Correct
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days.-Incorrect
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days.- -
Question 13 of 50
13. Question
Find the one which does not belong to that group ?
Correct
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.
Incorrect
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.
-
Question 14 of 50
14. Question
Product of two co-prime numbers is 117. Their L.C.M should be:
Correct
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117.Incorrect
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117. -
Question 15 of 50
15. Question
If the price has fallen by 10% what percent of its consumption be: increased so that the expenditure may be the same as before?
Correct
100 – 10 = 90
90——10
100——? => 11 1/9%Incorrect
100 – 10 = 90
90——10
100——? => 11 1/9% -
Question 16 of 50
16. Question
A man gets a simple interest of Rs.500 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate.
Correct
Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.500
(P)(8)(5)/100 = 500
P = 1250
C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years
=2500{ [1 + 5/100]2 – 1} = 2500{ 212 – 202 /202}
= 2500/400(441 – 400)
= 25/4(41) = 1025/4 = Rs.256.25Incorrect
Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.500
(P)(8)(5)/100 = 500
P = 1250
C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years
=2500{ [1 + 5/100]2 – 1} = 2500{ 212 – 202 /202}
= 2500/400(441 – 400)
= 25/4(41) = 1025/4 = Rs.256.25 -
Question 17 of 50
17. Question
The ratio of the volumes of a cube to that of the sphere which will fit inside the cube is?
Correct
a3 : a3/8 * 4/3 π => 6: π
Incorrect
a3 : a3/8 * 4/3 π => 6: π
-
Question 18 of 50
18. Question
What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
Correct
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1025
820x + 1025 * 441
x = 551.25
So, value of each installment = Rs. 551.25Incorrect
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1025
820x + 1025 * 441
x = 551.25
So, value of each installment = Rs. 551.25 -
Question 19 of 50
19. Question
The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?
Correct
(5 * 3.5)/2 = 8.75
Incorrect
(5 * 3.5)/2 = 8.75
-
Question 20 of 50
20. Question
Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48.
Correct
P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547Incorrect
P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547 -
Question 21 of 50
21. Question
A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?
Correct
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
Incorrect
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
-
Question 22 of 50
22. Question
The third proportional to 1 and 2 is?
Correct
(2*2)/1 = 4
Incorrect
(2*2)/1 = 4
-
Question 23 of 50
23. Question
I. a3 – 988 = 343,
II. b2 – 72 = 49 to solve both the equations to find the values of a and b?Correct
a3 = 1331 => a = 11
b2 = 121 => b = ± 11
a ≥ bIncorrect
a3 = 1331 => a = 11
b2 = 121 => b = ± 11
a ≥ b -
Question 24 of 50
24. Question
Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:
Correct
Let the required numbers be x, 2x and 3x. Then, their H.C.F = x. So, x = 12.
The numbers are 12, 24, 36.Incorrect
Let the required numbers be x, 2x and 3x. Then, their H.C.F = x. So, x = 12.
The numbers are 12, 24, 36. -
Question 25 of 50
25. Question
A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:
Correct
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12%Incorrect
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12% -
Question 26 of 50
26. Question
The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?
Correct
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60Incorrect
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60 -
Question 27 of 50
27. Question
If x = √196 + √200, then x/2 + 2/x is?
Correct
x = 14 + 10√2
x/2 = 7 + 5√2
2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7
x/2 + 2/x = 10√2 = 2√50Incorrect
x = 14 + 10√2
x/2 = 7 + 5√2
2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7
x/2 + 2/x = 10√2 = 2√50 -
Question 28 of 50
28. Question
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Correct
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
Therefore 20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.Incorrect
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
Therefore 20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m. -
Question 29 of 50
29. Question
If the sum of one-half of a number exceeds one-third of that number by 7 1/3, the number is:
Correct
Let the number be x. Then,
(1/2 x + 1/5 x) – 1/3 x = 22/3
11/30 x = 22/3
x = 20Incorrect
Let the number be x. Then,
(1/2 x + 1/5 x) – 1/3 x = 22/3
11/30 x = 22/3
x = 20 -
Question 30 of 50
30. Question
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
Correct
Let A, B, C represent their respective weights.
Then, we have:
A + B + C = (45 * 3) = 135 — (i)
A + B = (40 * 2) = 80 — (ii)
B + C = (43 * 2) = 86 — (iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)
Subtracting (i) from (iv), we get: B = 31
B’s weight = 31 kg.Incorrect
Let A, B, C represent their respective weights.
Then, we have:
A + B + C = (45 * 3) = 135 — (i)
A + B = (40 * 2) = 80 — (ii)
B + C = (43 * 2) = 86 — (iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)
Subtracting (i) from (iv), we get: B = 31
B’s weight = 31 kg. -
Question 31 of 50
31. Question
In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?
Correct
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528Incorrect
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528 -
Question 32 of 50
32. Question
Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
Correct
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6Incorrect
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6 -
Question 33 of 50
33. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 -
Question 34 of 50
34. Question
On dividing number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder?
Correct
Let x be the number and y be the quotient.
Then, x = 357 * y + 39
= (17 * 21 * y) + (17 * 2) + 5
= 17 * (21y + 2) + 5.
Required remainder = 5.Incorrect
Let x be the number and y be the quotient.
Then, x = 357 * y + 39
= (17 * 21 * y) + (17 * 2) + 5
= 17 * (21y + 2) + 5.
Required remainder = 5. -
Question 35 of 50
35. Question
The tens digit of a two-digit number is two more than its unit digit. The two-digit number is 7 times the sum of the digits. Find the units digits?
Correct
Let the two-digit number be 10a + b
a = b + 2 — (1)
10a + b = 7(a + b) => a = 2b
Substituting a = 2b in equation (1), we get
2b = b + 2 => b = 2
Hence the units digit is: 2.Incorrect
Let the two-digit number be 10a + b
a = b + 2 — (1)
10a + b = 7(a + b) => a = 2b
Substituting a = 2b in equation (1), we get
2b = b + 2 => b = 2
Hence the units digit is: 2. -
Question 36 of 50
36. Question
A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
Correct
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18Incorrect
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18 -
Question 37 of 50
37. Question
How many numbers up to 300 and 700 are divisible by 2, 3 and 7 both together?
Correct
(700 – 300)/42 = 9 22/42 => 9 Numbers
Incorrect
(700 – 300)/42 = 9 22/42 => 9 Numbers
-
Question 38 of 50
38. Question
The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
Correct
P = 144(100/5)2 => P = 3600
Incorrect
P = 144(100/5)2 => P = 3600
-
Question 39 of 50
39. Question
Nitin’s salary is reduced by 10% and then reduced salary is increased by 10%. Find ,how many percentage his present salary is less as compared to his previous salary?
Correct
10*10
——– = 1%
100Incorrect
10*10
——– = 1%
100 -
Question 40 of 50
40. Question
The bus fare for two persons for travelling between Agra and Aligarh id four-thirds the train fare between the same places for one person. The total fare paid by 6 persons travelling by bus and 8 persons travelling by train between the two places is Rs.1512. Find the train fare between the two places for one person?
Correct
Let the train fare between the two places for one person be Rs.t
Bus fare between the two places for two persons Rs.4/3 t
=> 6/2 (4/3 t) + 8(t) = 1512
=> 12t = 1512 => t = 126.Incorrect
Let the train fare between the two places for one person be Rs.t
Bus fare between the two places for two persons Rs.4/3 t
=> 6/2 (4/3 t) + 8(t) = 1512
=> 12t = 1512 => t = 126. -
Question 41 of 50
41. Question
The triplicate ratio of 1:2 is?
Correct
13: 23 = 1:8
Incorrect
13: 23 = 1:8
-
Question 42 of 50
42. Question
12(13/18) + 16(11/27) – 10(5/9) = ?
Correct
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)Incorrect
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54) -
Question 43 of 50
43. Question
Find the nearest to 25268 which is exactly divisible by 467?
Correct
Incorrect
-
Question 44 of 50
44. Question
A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture?
Correct
70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ——- 63
12 1/2% ——-? => 9-7=2Incorrect
70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ——- 63
12 1/2% ——-? => 9-7=2 -
Question 45 of 50
45. Question
How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Correct
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 – 800 = 500 metersIncorrect
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 – 800 = 500 meters -
Question 46 of 50
46. Question
The number of permutations of the letters of the word ‘MESMERISE’ is_.
Correct
n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern ‘MESMERISE’ consists of 10 letters of which there are 2M’s, 3E’s, 2S’s and 1I and 1R.
Number of arrangements = 9!/(2!)2 3!Incorrect
n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern ‘MESMERISE’ consists of 10 letters of which there are 2M’s, 3E’s, 2S’s and 1I and 1R.
Number of arrangements = 9!/(2!)2 3! -
Question 47 of 50
47. Question
After 38 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it?
Correct
95% ———– 38
5% ———— ? => 2 litersIncorrect
95% ———– 38
5% ———— ? => 2 liters -
Question 48 of 50
48. Question
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Correct
Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 => x = 50 km/hr.Incorrect
Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 => x = 50 km/hr. -
Question 49 of 50
49. Question
The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
Correct
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Incorrect
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
-
Question 50 of 50
50. Question
If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?
Correct
Given that, cost price of 50 article is equal to selling price of 40 articles.
Let cost price of one article = Rs. 1
Selling price of 40 articles = Rs. 50
But Cost price of 40 articles = Rs. 40
Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%Incorrect
Given that, cost price of 50 article is equal to selling price of 40 articles.
Let cost price of one article = Rs. 1
Selling price of 40 articles = Rs. 50
But Cost price of 40 articles = Rs. 40
Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%
