RRB ALP Online Test Series 2, RRB ALP Mock Test, RRB Quiz Series 2
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RRB ALP Online Test in English – Series 2, RRB ALP Free Online Test Series 2. RRB Exam Online Test 2024, RRB ALP Free Mock Test Exam 2024. RRB ALP Exam Free Online Quiz 2024, RRB ALP Full Online Mock Test Series 2nd in English. RRB Online Test for All Subjects, RRB ALP Free Mock Test Series in English. RRB ALP Free Mock Test Series 2. RRB ALP English Language Online Test in English Series 2nd. RRB ALP Quantitative Aptitude Quiz 2024, RRB ALP Reasoning Ability Free Online Test. Take RRB ALP Online Quiz. The RRB ALP Full online mock test paper is free for all students. RRB ALP Question and Answers in English and Hindi Series 2. Here we are providing RRB ALP Full Mock Test Paper in English. RRB ALP Mock Test Series 2nd 2024. Now Test your self for RRB ALP Exam by using below quiz…
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Question 1 of 50
1. Question
Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
Correct
1/20 + 1/30 – 1/40 = 7/120
120/7 = 17 1/7Incorrect
1/20 + 1/30 – 1/40 = 7/120
120/7 = 17 1/7 -
Question 2 of 50
2. Question
2222.2 + 222.22 + 22.222 = ?
Correct
Incorrect
-
Question 3 of 50
3. Question
In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
Correct
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 – 7.50) / (7.50 – 6) = 5/6Incorrect
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 – 7.50) / (7.50 – 6) = 5/6 -
Question 4 of 50
4. Question
How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Correct
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 secIncorrect
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec -
Question 5 of 50
5. Question
How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
Correct
Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.Incorrect
Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec. -
Question 6 of 50
6. Question
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Correct
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.Incorrect
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec. -
Question 7 of 50
7. Question
There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs. 2288, then what was the price of the article initially?
Correct
Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 – 20% of 130 = 130 – 26 = Rs. 104.
In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
But present price of the article is Rs. 2288
for 114.4 —> 100 ; 2288 —> ?
Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000.Incorrect
Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 – 20% of 130 = 130 – 26 = Rs. 104.
In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
But present price of the article is Rs. 2288
for 114.4 —> 100 ; 2288 —> ?
Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000. -
Question 8 of 50
8. Question
Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
Correct
Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12:15:16Incorrect
Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12:15:16 -
Question 9 of 50
9. Question
A can do a work in 9 days and B can do the same work in 18 days. If they work together, in how many days will they complete the work?
Correct
One day’s work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.
Incorrect
One day’s work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.
-
Question 10 of 50
10. Question
If the selling price of 50 articles is equal to the cost price of 40 articles, then the loss or gain percent is:
Correct
Let C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 40.
Loss % = 10/50 * 100 = 20%Incorrect
Let C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 40.
Loss % = 10/50 * 100 = 20% -
Question 11 of 50
11. Question
Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X’s present age in years?
Correct
Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X’s present age = 5x = 35 years.Incorrect
Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X’s present age = 5x = 35 years. -
Question 12 of 50
12. Question
pipes P and Q would fill a cistern 18 and 24 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be just filled in 12 minutes?
Correct
x/18 + 12/24 = 1
x = 9Incorrect
x/18 + 12/24 = 1
x = 9 -
Question 13 of 50
13. Question
In digging a pond 20 m * 10 m * 5 m the volumes of the soil extracted will be?
Correct
20 * 10 * 5 = 1000
Incorrect
20 * 10 * 5 = 1000
-
Question 14 of 50
14. Question
The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?
Correct
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.Incorrect
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. -
Question 15 of 50
15. Question
A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Correct
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.Incorrect
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m. -
Question 16 of 50
16. Question
Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak’s share is:
Correct
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400.Incorrect
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400. -
Question 17 of 50
17. Question
What is the difference between the C.I. on Rs. 5000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly?
Correct
C.I. when interest is compounded yearly
= [5000 * (1 + 4/100) * (1 + (1/2 * 4)/100]
= 5000 * 26/25 * 51/50 = Rs. 5304
C.I. when interest is compounded half-yearly
= [5000 * (1 + 2/100)2]
= (5000 * 51/50 * 51/50 * 51/50) = Rs. 5306.04 Difference = (5306.04 – 5304) = Rs. 2.04.Incorrect
C.I. when interest is compounded yearly
= [5000 * (1 + 4/100) * (1 + (1/2 * 4)/100]
= 5000 * 26/25 * 51/50 = Rs. 5304
C.I. when interest is compounded half-yearly
= [5000 * (1 + 2/100)2]
= (5000 * 51/50 * 51/50 * 51/50) = Rs. 5306.04 Difference = (5306.04 – 5304) = Rs. 2.04. -
Question 18 of 50
18. Question
A lends Rs. 2500 to B and a certain to C at the same time at 7% p.a. simple interest. If after 4 years, A altogether receives Rs. 1120 as interest from B and C, then the sum lent to C is?
Correct
Let the sum lent to C be Rs. x. Then,
(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120
7/25 x = (1120 – 700) => x = 1500Incorrect
Let the sum lent to C be Rs. x. Then,
(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120
7/25 x = (1120 – 700) => x = 1500 -
Question 19 of 50
19. Question
Thrice the square of a natural number decreased by 4 times the number is equal to 50 more than the number. The number is:
Correct
Let the number be x. Then,
3x2 – 4x = x + 503x2 – 5x – 50 = 0(3x + 10)(x – 5) = 0x = 5Incorrect
Let the number be x. Then,
3x2 – 4x = x + 503x2 – 5x – 50 = 0(3x + 10)(x – 5) = 0x = 5 -
Question 20 of 50
20. Question
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.
Correct
A = 5000(51/50)3
= 5306.04
5000
———–
306.04Incorrect
A = 5000(51/50)3
= 5306.04
5000
———–
306.04 -
Question 21 of 50
21. Question
A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 6 days. How long will C take to do it?
Correct
2c = ¼ + 1/6 – 1/3 = 1/12
c = 1/24 => 24 daysIncorrect
2c = ¼ + 1/6 – 1/3 = 1/12
c = 1/24 => 24 days -
Question 22 of 50
22. Question
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in?
Correct
(A + B + C)’s 1 day work = 1/6;
(A + B)’s 1 day work = 1/8(B + C)’s 1 day work = 1/12(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)= (1/3 – 5/24) = 1/8So, A and C together will do the work in 8 days.Incorrect
(A + B + C)’s 1 day work = 1/6;
(A + B)’s 1 day work = 1/8(B + C)’s 1 day work = 1/12(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)= (1/3 – 5/24) = 1/8So, A and C together will do the work in 8 days. -
Question 23 of 50
23. Question
The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is -.
Correct
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆Incorrect
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆ -
Question 24 of 50
24. Question
Find the roots of the quadratic equation: x2 + 2x – 15 = 0?
Correct
x2 + 5x – 3x – 15 = 0
x(x + 5) – 3(x + 5) = 0
(x – 3)(x + 5) = 0
=> x = 3 or x = -5.Incorrect
x2 + 5x – 3x – 15 = 0
x(x + 5) – 3(x + 5) = 0
(x – 3)(x + 5) = 0
=> x = 3 or x = -5. -
Question 25 of 50
25. Question
A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
Correct
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50
Incorrect
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50
-
Question 26 of 50
26. Question
Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.
Correct
60(x + 1) = 64x
X = 15
60 * 16 = 960 kmIncorrect
60(x + 1) = 64x
X = 15
60 * 16 = 960 km -
Question 27 of 50
27. Question
The ratio of the present ages of Giri and Hari is 5 : 8. 12 years hence, the ratio of their ages will be 11 : 14. Find the difference in their present ages?
Correct
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x – 5x = 3x = 6 years.Incorrect
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x – 5x = 3x = 6 years. -
Question 28 of 50
28. Question
Find the least number of five digits which is exactly divisible by 12, 15 and 18?
Correct
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080Incorrect
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080 -
Question 29 of 50
29. Question
A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.
Correct
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A-(B+C) = 160/3 – 140/3 = 20/3
20/3 —- 200
100 —- ? => 3000Incorrect
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A-(B+C) = 160/3 – 140/3 = 20/3
20/3 —- 200
100 —- ? => 3000 -
Question 30 of 50
30. Question
3/7 of 4/9 of 2/5 of 7560 = (?)2
Correct
?2 = 3/7 * 4/9 * 2/5 * 7560
=> ?2 = 576 = 242? = 24Incorrect
?2 = 3/7 * 4/9 * 2/5 * 7560
=> ?2 = 576 = 242? = 24 -
Question 31 of 50
31. Question
Identify the greatest numbers: 450, 2100, 1625
Correct
450 = (22)50 = 2100 => 1625 = (24)25 = 2100
Hence, 450, 2100 and 16425 are all equal.Incorrect
450 = (22)50 = 2100 => 1625 = (24)25 = 2100
Hence, 450, 2100 and 16425 are all equal. -
Question 32 of 50
32. Question
Three persons A, B and C divide a certain amount of money such that A’s share is Rs. 4 less than half of the total amount, B’s share is Rs. 8 more than half of what is left and finally C takes the rest which is Rs. 14. Find the total amount they initially had with them?
Correct
Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C’s share was Rs. 14
we have, x + y + 14 = p —– (1)
From the given data, x = (p/2) – 4 —– (2)
Remaining amount = p – (p/2 – 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)
From (1), (2) and (3)
p/2 – 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80.Incorrect
Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C’s share was Rs. 14
we have, x + y + 14 = p —– (1)
From the given data, x = (p/2) – 4 —– (2)
Remaining amount = p – (p/2 – 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)
From (1), (2) and (3)
p/2 – 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80. -
Question 33 of 50
33. Question
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Correct
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 secIncorrect
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec -
Question 34 of 50
34. Question
Two varieties of wheat – A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
Correct
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50Incorrect
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50 -
Question 35 of 50
35. Question
Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
Correct
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60Incorrect
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60 -
Question 36 of 50
36. Question
A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Correct
40*(40/100) = 16 — 64
? — 12 => Rs.3Incorrect
40*(40/100) = 16 — 64
? — 12 => Rs.3 -
Question 37 of 50
37. Question
A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. another man leaves the point give at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
Correct
Incorrect
-
Question 38 of 50
38. Question
35 + 15 * 1.5 = ?
Correct
Given Exp. = 35 + 15 * 3/2
= 35 + 45/2 = 35 + 22.5 = 57.5Incorrect
Given Exp. = 35 + 15 * 3/2
= 35 + 45/2 = 35 + 22.5 = 57.5 -
Question 39 of 50
39. Question
What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12% p.a.?
Correct
Amount = [25000 * (1 + 12/100)3]
= 25000 * 28/25 * 28/25 * 28/25 = Rs. 35123.20C.I. = (35123.20 – 25000) = Rs. 10123.20Incorrect
Amount = [25000 * (1 + 12/100)3]
= 25000 * 28/25 * 28/25 * 28/25 = Rs. 35123.20C.I. = (35123.20 – 25000) = Rs. 10123.20 -
Question 40 of 50
40. Question
Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x?
Correct
Let the present ages of Mahesh, Nilesh and Ramesh be m, n and r respectively.
m/n = 5/x —— (1)
m = r – 18 —— (2)
r + 9 = 47 —— (3)
m – n = r —– (4)
(3) => r = 47 – 9 = 38 years
(2) => m = 38 -18 = 20 years
(1) => 20/n = 5/x => n = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5Incorrect
Let the present ages of Mahesh, Nilesh and Ramesh be m, n and r respectively.
m/n = 5/x —— (1)
m = r – 18 —— (2)
r + 9 = 47 —— (3)
m – n = r —– (4)
(3) => r = 47 – 9 = 38 years
(2) => m = 38 -18 = 20 years
(1) => 20/n = 5/x => n = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5 -
Question 41 of 50
41. Question
A man buys milk at a certain rate per liter and after adding water to it sells the mixture at the same rate. Find in what ration he much mix water to milk so as to gain 20% on his outlay?
Correct
Incorrect
-
Question 42 of 50
42. Question
P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
Correct
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.Incorrect
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together. -
Question 43 of 50
43. Question
Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
Correct
C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6%Incorrect
C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6% -
Question 44 of 50
44. Question
One train is traveling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
Correct
45 * 5/18 = 10
25:20 => 5:4Incorrect
45 * 5/18 = 10
25:20 => 5:4 -
Question 45 of 50
45. Question
Find the greatest four digit number which leaves respective remainders of 2 and 5 when divided by 15 and 24.
Correct
Since the difference between the divisors and the respective remainders is not constant, back substitution is the convenient method. None of the given numbers is satisfying the condition.
Incorrect
Since the difference between the divisors and the respective remainders is not constant, back substitution is the convenient method. None of the given numbers is satisfying the condition.
-
Question 46 of 50
46. Question
A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
Correct
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.Incorrect
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. -
Question 47 of 50
47. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 daysIncorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days -
Question 48 of 50
48. Question
What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
Correct
d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1Incorrect
d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1 -
Question 49 of 50
49. Question
If a : b = 4 : 1, then find (a – 3b)/(2a – b).
Correct
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7Incorrect
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7 -
Question 50 of 50
50. Question
If one third of 3/4 of a number is 21. Then find the number?
Correct
x * 1/3 * 3/4 =21 => x = 84
Incorrect
x * 1/3 * 3/4 =21 => x = 84