DCCB Mock Test in English Series 4, DCCB Online Test Series 4
Finish Quiz
0 of 50 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
Information
DCCB Mock Test in English Series 4, DCCB Online Test Series 4, DCCB Free Online Test Series 4. RRB Exam Online Test 2024, DCCB Free Mock Test Exam 2024. DCCB Exam Free Online Quiz 2024, DCCB Full Online Mock Test Series 4th in English. RRB Online Test for All Subjects, DCCB Free Mock Test Series in English. DCCB Free Mock Test Series 4. DCCB English Language Online Test in English Series 4th. DCCB Quantitative Aptitude Quiz 2024, DCCB Reasoning Ability Free Online Test. Take DCCB Online Quiz. The DCCB Full online mock test paper is free for all students. DCCB Question and Answers in English and Hindi Series 4. Here we are providing DCCB Full Mock Test Paper in English. DCCB Mock Test Series 4th 2024. Now Test your self for DCCB Exam by using below quiz…
This paper has 50 questions.
Time allowed is 50 minutes.
The DCCB Online Test Series 4th, DCCB Free Online Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 50 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
| Average score |
|
| Your score |
|
Categories
- Not categorized 0%
| Pos. | Name | Entered on | Points | Result |
|---|---|---|---|---|
| Table is loading | ||||
| No data available | ||||
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
- Answered
- Review
-
Question 1 of 50
1. Question
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
Correct
160 = (180*4*R)/100
R = 5%Incorrect
160 = (180*4*R)/100
R = 5% -
Question 2 of 50
2. Question
Varma can read a book in k minutes. What part of the book can he read in 8 minutes?(k>8)
Correct
Part of the book he can read in 1 minute = 1/k
Part of the book he can read in 8 minutes =8/k.Incorrect
Part of the book he can read in 1 minute = 1/k
Part of the book he can read in 8 minutes =8/k. -
Question 3 of 50
3. Question
Solve for m if 36 (6m) = (216)3m+4
Correct
36 (6m) = (216)3m+4 => 62 6m = (63)3m+4 => 62+m = 69m+12 Equating powers of 6 on both sides.
m + 2 = 9m + 12 => -10 = 8m => m = -5/4Incorrect
36 (6m) = (216)3m+4 => 62 6m = (63)3m+4 => 62+m = 69m+12 Equating powers of 6 on both sides.
m + 2 = 9m + 12 => -10 = 8m => m = -5/4 -
Question 4 of 50
4. Question
A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
Correct
Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000Incorrect
Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000 -
Question 5 of 50
5. Question
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/6 equals -.
Correct
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16
= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32
= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224
= 12 + 25/224 = 12 25/224Incorrect
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16
= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32
= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224
= 12 + 25/224 = 12 25/224 -
Question 6 of 50
6. Question
A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
Correct
65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900Incorrect
65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900 -
Question 7 of 50
7. Question
An amount of Rs.1560 was divided among A, B and C in the ratio 1/2:1/3:1/4. Find the share of C?
Correct
Let the shares of A, B and C be a, b and c respectively.
a:b:c = 1/2:1/3:1/4
a:b:c = 6/12:4/12:3:12 = 6:4:3
Share of C = 3/13 * 1560 = Rs.360.Incorrect
Let the shares of A, B and C be a, b and c respectively.
a:b:c = 1/2:1/3:1/4
a:b:c = 6/12:4/12:3:12 = 6:4:3
Share of C = 3/13 * 1560 = Rs.360. -
Question 8 of 50
8. Question
Some persons can do a piece of work in 12 days. Two times the number of these people will do half of that work in?
Correct
12/ (2 * 2) = 3 days
Incorrect
12/ (2 * 2) = 3 days
-
Question 9 of 50
9. Question
The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is -.
Correct
x Not younger_______ ↑
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320Incorrect
x Not younger_______ ↑
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320 -
Question 10 of 50
10. Question
The length and breadth of a rectangle is increased by 10% and 25% respectively. What is the increase in the area?
Correct
100 * 100 = 10000
110 * 125 = 13750
———–
3750
10000 —— 3750
100 ——- ? => 37.5%Incorrect
100 * 100 = 10000
110 * 125 = 13750
———–
3750
10000 —— 3750
100 ——- ? => 37.5% -
Question 11 of 50
11. Question
Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?
Correct
A’s one day’s work = 1/30
B’s one day’s work = 1/45
(A + B)’s one day’s work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6.Incorrect
A’s one day’s work = 1/30
B’s one day’s work = 1/45
(A + B)’s one day’s work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6. -
Question 12 of 50
12. Question
If 25% of x is 15 less than 15% of 1500, then x is?
Correct
25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225
Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840.Incorrect
25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225
Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840. -
Question 13 of 50
13. Question
A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after one year service. He served only for 9 months and received uniform and Rs.650, find the price of the uniform?
Correct
9/12 = 3/4 * 900 = 675
650
————-
25
1/4 ——– 25
1 ——— ? => Rs.100Incorrect
9/12 = 3/4 * 900 = 675
650
————-
25
1/4 ——– 25
1 ——— ? => Rs.100 -
Question 14 of 50
14. Question
There is 60% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
Correct
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 – 1}]
= 12000 * 331/1000 = Rs. 3972Incorrect
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 – 1}]
= 12000 * 331/1000 = Rs. 3972 -
Question 15 of 50
15. Question
How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Correct
Speed of train relative to man = 63 – 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.Incorrect
Speed of train relative to man = 63 – 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec. -
Question 16 of 50
16. Question
The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
Correct
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm.Incorrect
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm. -
Question 17 of 50
17. Question
There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
Correct
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.Incorrect
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25. -
Question 18 of 50
18. Question
The area of a base of a cone is 30 cm2. If the height of the cone is 6cm, find its volume?
Correct
πr2 = 30 h = 6
1/3 * 30 * 6 = 60Incorrect
πr2 = 30 h = 6
1/3 * 30 * 6 = 60 -
Question 19 of 50
19. Question
Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?
Correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min.Incorrect
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min. -
Question 20 of 50
20. Question
What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?
Correct
1347
7431
————
6084Incorrect
1347
7431
————
6084 -
Question 21 of 50
21. Question
A man purchased 15 pens, 12 books, 10 pencils and 5 erasers. The cost of each pen is Rs.36, each book is Rs.45, each pencil is Rs.8, and the cost of each eraser is Rs.40 less than the combined costs of pen and pencil. Find the total amount spent?
Correct
Incorrect
-
Question 22 of 50
22. Question
Subtracting 10% from X is the same as multiplying X by what number?
Correct
X – (10/100) X = X * ?
? = 90%Incorrect
X – (10/100) X = X * ?
? = 90% -
Question 23 of 50
23. Question
What is the unit digit in 7105 ?
Correct
Unit digit in 7105 = unit digit in [(74)26 * 7]
But, unit digit in (74)26 = 1
unit digit in 7105 = (1 * 7) = 7Incorrect
Unit digit in 7105 = unit digit in [(74)26 * 7]
But, unit digit in (74)26 = 1
unit digit in 7105 = (1 * 7) = 7 -
Question 24 of 50
24. Question
Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?
Correct
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———-
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000Incorrect
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———-
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000 -
Question 25 of 50
25. Question
A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?
Correct
Let the capital be Rs. x. Then,
(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50
32x – 31x = 6150 * 4
x = 24,600.Incorrect
Let the capital be Rs. x. Then,
(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50
32x – 31x = 6150 * 4
x = 24,600. -
Question 26 of 50
26. Question
(3a+1 9a+2 27a) / (3a-1 9a 27a+1) = ?
Correct
(3a+1 9a+2 27a) / (3a-1 9a 27a+1) = [3a+1 32(a+2) (33)a] / [3a-1 (32)a (33)a+1] = 36a+5 / 36a+2 = 33 = 27.
Incorrect
(3a+1 9a+2 27a) / (3a-1 9a 27a+1) = [3a+1 32(a+2) (33)a] / [3a-1 (32)a (33)a+1] = 36a+5 / 36a+2 = 33 = 27.
-
Question 27 of 50
27. Question
The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
Correct
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96.Incorrect
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96. -
Question 28 of 50
28. Question
A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?
Correct
lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10Incorrect
lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10 -
Question 29 of 50
29. Question
After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?
Correct
Given SP = Rs. 6800
Marked price = [SP(100)]/(100 – d%) = (6800 * 100)/(100 – 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000Incorrect
Given SP = Rs. 6800
Marked price = [SP(100)]/(100 – d%) = (6800 * 100)/(100 – 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000 -
Question 30 of 50
30. Question
Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions?
Correct
RS = 60 -40 = 20 * 5/18 = 100/18
T = 50
D = 50 * 100/18 = 2500/9
RS = 60 + 40 = 100 * 5/18
T = 2500/9 * 18/500 = 10 secIncorrect
RS = 60 -40 = 20 * 5/18 = 100/18
T = 50
D = 50 * 100/18 = 2500/9
RS = 60 + 40 = 100 * 5/18
T = 2500/9 * 18/500 = 10 sec -
Question 31 of 50
31. Question
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Correct
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T – C = 100Incorrect
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T – C = 100 -
Question 32 of 50
32. Question
The average of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?
Correct
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years.Incorrect
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years. -
Question 33 of 50
33. Question
96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Correct
x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42Incorrect
x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42 -
Question 34 of 50
34. Question
If p, q and r are positive integers and satisfy x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p, then the value of x is?
Correct
Hence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p
=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)
=> x = (p + q + r)/(r + q + p) = 1.Incorrect
Hence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p
=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)
=> x = (p + q + r)/(r + q + p) = 1. -
Question 35 of 50
35. Question
At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
Correct
Let sum = x. Then, S.I. = 2x/5, Time = 10 years.
Rate = (100 * 2x) / (x * 5 * 10) = 4%Incorrect
Let sum = x. Then, S.I. = 2x/5, Time = 10 years.
Rate = (100 * 2x) / (x * 5 * 10) = 4% -
Question 36 of 50
36. Question
Find the number of factors of 300 excluding 1 and itself.
Correct
300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself.Incorrect
300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself. -
Question 37 of 50
37. Question
Find the roots of quadratic equation: x2 + x – 42 = 0?
Correct
x2 + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = -7, 6Incorrect
x2 + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = -7, 6 -
Question 38 of 50
38. Question
The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?
Correct
Incorrect
-
Question 39 of 50
39. Question
Find the one which does not belong to that group ?
Correct
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.
Incorrect
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.
-
Question 40 of 50
40. Question
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.
Correct
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.Incorrect
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively. -
Question 41 of 50
41. Question
Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
Correct
(800*3*3)/100 = 72
920 + 72 = 992Incorrect
(800*3*3)/100 = 72
920 + 72 = 992 -
Question 42 of 50
42. Question
A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
Correct
Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 – 96 =Rs. 4
100 —— 4
? ——— 200 => 5000Incorrect
Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 – 96 =Rs. 4
100 —— 4
? ——— 200 => 5000 -
Question 43 of 50
43. Question
Find the one which does not belong to that group ?
Correct
Except 4242, all other numbers are divisible by 11.
Incorrect
Except 4242, all other numbers are divisible by 11.
-
Question 44 of 50
44. Question
Which of the following number is divisible by 4 and 9?
Correct
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9.Incorrect
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9. -
Question 45 of 50
45. Question
A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest?
Correct
If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.
Let the earlier rate of interest be x%.
Now it will be (x + 3)%
% increase = (x + 3) – x/x * 100 = 25
=> x = 12Incorrect
If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.
Let the earlier rate of interest be x%.
Now it will be (x + 3)%
% increase = (x + 3) – x/x * 100 = 25
=> x = 12 -
Question 46 of 50
46. Question
How many figures are required to number the pages the pages of a book containing 365 pages?
Correct
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
———–
987Incorrect
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
———–
987 -
Question 47 of 50
47. Question
A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
Correct
S = 180/6 * 18/5 = 108 kmph
Incorrect
S = 180/6 * 18/5 = 108 kmph
-
Question 48 of 50
48. Question
Ten percent of Ram’s monthly salary is equal to eight percent of Shyam’s monthly salary. Shyam’s monthly salary is twice Abhinav’s monthly salary. If Abhinav’s annual salary is Rs. 1.92 lakhs, find Ram’s monthly salary?
Correct
Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.
10/100 r = 8/100 s
r = 4/5 s
Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs
s = 2(0.16 lakhs) = 0.32 lakhs
r = 4/5(0.32 lakhs) = Rs. 25600Incorrect
Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.
10/100 r = 8/100 s
r = 4/5 s
Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs
s = 2(0.16 lakhs) = 0.32 lakhs
r = 4/5(0.32 lakhs) = Rs. 25600 -
Question 49 of 50
49. Question
In what time a sum of money double itself at 3% per annum simple interest?
Correct
P = (P*3*R)/100
R = 33 1/3%Incorrect
P = (P*3*R)/100
R = 33 1/3% -
Question 50 of 50
50. Question
The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is -.
Correct
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆Incorrect
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆
