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Quantitative Aptitude Questions for IBPS SO Prelims Online Test, IBPS SO Free Mock Test Series. IBPS Free Mock Test for IT Officer. The below online test on IBPS Specialist Officer Recruitment will help you for preperation of the post of IT Officer, Agricultural Field Officer, Rajbhasha Adhikari, Law Officer, HR/Personnel Officer, Marketing Officer. IBPS Quantitative Aptitude Online Test in English. IBPS SO Quantitative Aptitude Quiz 2024. The IBPS Full online mock test paper is free for all students. IBPS Mock test for Quantitative Aptitude Subject Via Online Mode. Here we are providing Quantitative Aptitude Question for IBPS SO Exam in English. IBPS SO IT Officer Mock Test Series 2024. Now Test your self for IBPS Exam by using below quiz… This paper has 50 questions. Time allowed is 40 minutes. The IBPS online Mock Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
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You have reached 0 of 0 points, (0) 267, 244, 219, 190, ?, 100 The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series: 265, 264, 272, 245, 309, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series: -13, +23, -33, +43, -53 -13, +23, -33, +43, -53 0.5, 2, 7, 29, 146, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series: *2 + 1, *3 + 1, *4 + 1, *5 + 1 *2 + 1, *3 + 1, *4 + 1, *5 + 1 0.5, 2, 5, 12.5, 34.25, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series: *1 + 1.5, *1.5 + 2, *2 + 2.5, *2.5 + 3, *3 + 3.5 *1 + 1.5, *1.5 + 2, *2 + 2.5, *2.5 + 3, *3 + 3.5 512, ?, 256, 64, 8, 0.5 The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series: *1, *1/2, *1/4, *1/8, *1/16 *1, *1/2, *1/4, *1/8, *1/16 √? + √1335 * 24 – 13.96 = 895 What approximate value should come in place of question mark (?) in the below given questions? √? +36*24 -14=895 √? +36*24 -14=895 (42.03% of 495.04 + 58.02% of 1200 ) / 9 = ? What approximate value should come in place of question mark (?) in the below given questions? (208+696)/9=100.44 (208+696)/9=100.44 (9117.88 – 8021.85 + 903.92) * 12 = 1500 * ? What approximate value should come in place of question mark (?) in the below given questions? (9118-8022+904) *12 =1500* ? (2000*12 /1500) = x X=15. (9118-8022+904) *12 =1500* ? (2000*12 /1500) = x X=15. {(4/7*15/4) / (3.5 -1.2) }2 = ? What approximate value should come in place of question mark (?) in the below given questions? [(60/28)/2.3]2 =x [(60/28)/2.3]2 =x If x=3.5 , y=4.5 , then {(y-x) (y-x)/y+x}*xy = ? What approximate value should come in place of question mark (?) in the below given questions? {(1*1)/8*15.75}= x {(1*1)/8*15.75}= x (87.65% of 7159.89 – 68.99% of 8939.89) * 6.06 = (?)2 What approximate value should come in place of question mark (?) in the below given questions? (6300 – 6168) * 6 =x 2 (6300 – 6168) * 6 =x 2 35 5/7% of 6510 + 77 7/9% of 5886 = ?% of 6126 + 50% of 5638 What approximate value should come in place of question mark (?) in the below given questions? 250/7% of 6510 + 700/9 % of 5886 =?% of 6126 + 50% of 5638 250/7% of 6510 + 700/9 % of 5886 =?% of 6126 + 50% of 5638 854.926 – 562.005 – 115.98 = 22.6% of (?) What approximate value should come in place of question mark (?) in the below given questions? 855 – 562 – 116 = 22.6% of x 855 – 562 – 116 = 22.6% of x (750/45) / 11/781 * 114/95 = ? What approximate value should come in place of question mark (?) in the below given questions? 750/45 * 781/11* 114/95 750/45 * 781/11* 114/95 15.332 – 12.942 + 22.062 – 35.65 = ? What approximate value should come in place of question mark (?) in the below given questions? 15 2 -132 + 222 -35.65 = x 15 2 -132 + 222 -35.65 = x I. 3×2 – 5x – 12 = 0 x = -4/3, 3 x = -4/3, 3 I. 2×2 + 11x + 14 = 0 x = -7/2, -2 x = -7/2, -2 I. 3×2 + 19x + 20 = 0 x = -5, -4/3 x = -5, -4/3 I. 4×2 – 9x – 9 = 0 x = -3/4, 3 x = -3/4, 3 I. 2×2 – 3x – 9 = 0 x = -3/2, 3 x = -3/2, 3 In two alloys A and B the ratio of zinc to copper is 4:5 and 2:7 respectively. Eighteen kg of the alloy A and 45 kg of the alloy B are mixed together to form a new alloy. what will be the ratio of Zinc and copper in the new alloy? Total Quantity of Zinc=4/9*18 + 2/9*45=8+10==>18 Total Quantity of Zinc=4/9*18 + 2/9*45=8+10==>18 If the manufacturer gains 10 %, the wholesale dealer 15 % and the retailer 25 %, then find the cost of production of a table if the retail price was Rs 1265 (125/100 *115/100*110/100 )*P =1265 (125/100 *115/100*110/100 )*P =1265 A began a business with Rs. 65,000. He was joined afterwards by B with Rs. 40,000. For how much period does B work, if the profits at the end of the year are divided in the ratio of 13 : 4? (65000*12)/(40000*x)=13/4 X= 3/2x=1/4 X=6. (65000*12)/(40000*x)=13/4 X= 3/2x=1/4 X=6. After three successive equal percentage rise in the salary the sum of 100 rupees turned into 140 rupees and 49 paise. Find the percentage rise in the salary. 12% of 100 ==>112 12% of 100 ==>112 A dishonest milk man mixed 1 liter of water for every 3 liters of milk and thus made up 36 liters of milk. If he now adds 15 liters of milk to mixture, find the ratio of milk and water in the new mixture: Quantity of milk and water in the 36 liter mixture; Quantity of milk and water in the 36 liter mixture; From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings? P=n(e)/n(s) =[(4*3)/(2*1)]/ [(52*51)/(2*1)] =6/1326=1/221. P=n(e)/n(s) =[(4*3)/(2*1)]/ [(52*51)/(2*1)] =6/1326=1/221. The average weight of 6 persons increases by 3 kg when a new person comes in place of one of them weighing 45 kg. What might be the weight of the new person ? Total weight increased = (6 x 3) kg = 18 kg. Total weight increased = (6 x 3) kg = 18 kg. The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle? Answer: A 2(l+b)/b=5/1 Answer: A 2(l+b)/b=5/1 A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital? Let B’s capital be Rs. x. Let B’s capital be Rs. x. 12 buckets of water fill a tank when the capacity of each tank is 13.5 liters. How many buckets will be needed to fill the same tank,if the capacity of each bucket is 9 liters? Capacity of the tank =(12 x 13.5) liters =162 liters. Capacity of the tank =(12 x 13.5) liters =162 liters. Study the bar chart carefully to answer the given questions. What is the difference between the number of passengers travelling from X to S and that from X to T? 12000 * (16-9)/100 12000 * (16-9)/100 Study the bar chart carefully to answer the given questions. What is the average no of passengers travelling from X to R, Q and S together? 12000* (15+22+16)/3 =120*53/3=2120. 12000* (15+22+16)/3 =120*53/3=2120. Study the bar chart carefully to answer the given questions. The no of passengers travelling from X to S is what percent more than the no of passengers travelling to P? [12000*12/100] 100 [12000*12/100] 100 Study the bar chart carefully to answer the given questions. What will be the central angle for passengers travelling from X to S ? 360 == 100 360 == 100 Study the bar chart carefully to answer the given questions. Passengers travelling from X to which station are the maximum in number? From bar graph, From bar graph, What is the number of employees in Finance Department of offices A and D? In A = 18 * 3/2 = 27 In A = 18 * 3/2 = 27 What is the number of employees in Other Departments of offices D and E? In D, in finance = 28, so in Others = 250 – (32+28) = 190 In D, in finance = 28, so in Others = 250 – (32+28) = 190 In Office C, 25%, 20% and 50% people in HR, Finance and Others Department respectively are females. What is the number of males in these departments in office C? In C, in HR = 16, so males = 75/100 * 16 = 12 In C, in HR = 16, so males = 75/100 * 16 = 12 What is the ratio of number of employees in Other Departments in offices A and D? In A, in others = 270 – (18+27) = 225 in D, in others = 190 Required ratio = 225 : 190 = 45 : 38 In A, in others = 270 – (18+27) = 225 in D, in others = 190 Required ratio = 225 : 190 = 45 : 38 What is the total number of employees in Finance Department in all offices? Required number 27+63+28+10+88 = 216 Required number 27+63+28+10+88 = 216 Two boats A and B starts from the two different places P and Q at the same time towards each other. If boat A is going downstream and other is going upstream, after how much time will they meet each other if their speeds are 15km/hr and 20km/hr respectively and if distance between the two places i.e P and Q is 210km? Time = Distance /Relative speed Time = Distance /Relative speed A company gives 5% of commission to a salesman upto the sale of 20,000 and a commission of 4% on the sales above 20,000. If the salesman deposited Rs.36,000 in the company after deducting his commission. Find his total sales (approx)? Ram purchases 750 articles at a cost of 60 paise/article. He fixed the selling price such that if he sold only 600 articles ,he would made a profit of 40% on the incidental charge. However 120 articles got damaged and able to sell only 630 articles at this price. Find his actual profit % as the percentage of total incidental charge if unsold articles are useless. Cost Price= 750 * 60/ 100 = Rs.450 Cost Price= 750 * 60/ 100 = Rs.450 A gold ring of 20 gm has gold and silver in the ratio 196:4 ,while another ring of 10 gm has in the ratio 8:2 .If both of them are molten and mixed together. Find the ratio of gold and silver in the resultant mixture? Amt. of gold in the first gold ring = (196/196+4)*20 = 19.6 gm Amt. of gold in the first gold ring = (196/196+4)*20 = 19.6 gm If a discount 20% on the marked price of an food item, the shopkeeper gets a profit of 40%. Find his percentage profit if he offers a discount of 40% on the same article ? (100 + %first profit ) [100- % 2nd discount/ 100 -% 1st discount ] – 100 (100 + %first profit ) [100- % 2nd discount/ 100 -% 1st discount ] – 100 In how many ways the letters of the word “EQUATION” can be arranged if it always starts with letter “E” and ends with letter “T” For this ,lets fix the letter E at the first position= 1! Way and fix T at the last position = 1! Way . For this ,lets fix the letter E at the first position= 1! Way and fix T at the last position = 1! Way . A , B and C hired a meadow jointly for the whole year. A puts 80 cows for 10 months, B puts 100 cows for 6 months and C puts 120 cows for 3 months. If A paid Rs. 400 as rent. Find the total rent for the meadow ? Find the ratio first , Find the ratio first , A tank has two pipes. The first pipe can fill it in 45 minutes and the second pipe can empty it in 1 hour. In what time will the empty tank be filled if the pipes be opened one at a time in alternate minutes? In 2 minutes -> +4 filled and -3 emptied = 1 litre filled In 2 minutes -> +4 filled and -3 emptied = 1 litre filled A bag contains 3 black and 5 red balls . A ball is drawn out of it and replaced in the bag. Two draws of two balls each are made ,the ball being replaced after the first draw. What is the chance that the balls were black in the first draw and red in the second draw? Req. Probability = 3C2/8C2 * 5C2/ 8C2 = 15 / 392 Req. Probability = 3C2/8C2 * 5C2/ 8C2 = 15 / 392 The difference between the simple interest received from two different banks on Rs. 700 for 3 years is Rs. 3. What is the difference between their rate of interest ( in p.a ) ? (3/ 700) *( 100 /3) = 1/7 = 0.143% (3/ 700) *( 100 /3) = 1/7 = 0.143%IBPS SO Prelims Quantitative Aptitude Free Online Mock Test - 1
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1. Question
2. Question
3. Question
4. Question
5. Question
6. Question
√? +850=895
√?=45
X=45*45=2025.
√? +850=895
√?=45
X=45*45=2025.
7. Question
8. Question
9. Question
X={15/16}2 ==> 0.87.
X={15/16}2 ==> 0.87.
10. Question
X= 15.75/8=2.
X= 15.75/8=2.
11. Question
132 * 6 = x 2
792= x 2
ie x=28.
132 * 6 = x 2
792= x 2
ie x=28.
12. Question
2325 + 4578 – 2819 = x/100 *6126 +2819
(4084 *100 ) /6126 = x
X=66.66.
2325 + 4578 – 2819 = x/100 *6126 +2819
(4084 *100 ) /6126 = x
X=66.66.
13. Question
177 =23/100 * x
X=770
177 =23/100 * x
X=770
14. Question
=(10*71*36 )/ 19
=1420.
=(10*71*36 )/ 19
=1420.
15. Question
225-169+484-35.65 = x
X= 504.
225-169+484-35.65 = x
X= 504.
16. Question
II. 4y2 – 9y – 9 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
y = -3/4, 3
Put all values on number line and analyze the relationship
-4/3………..-3/4……3
y = -3/4, 3
Put all values on number line and analyze the relationship
-4/3………..-3/4……3
17. Question
II. 3y2 – 7y – 6 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
y = -2/3, 3
Put all values on number line and analyze the relationship
-7/2………-2………..-2/3…………3
y = -2/3, 3
Put all values on number line and analyze the relationship
-7/2………-2………..-2/3…………3
18. Question
II. 4y2 – 13y – 12 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
y = -3/4, 4
Put all values on number line and analyze the relationship
-5………-4/3……….-3/4………4
y = -3/4, 4
Put all values on number line and analyze the relationship
-5………-4/3……….-3/4………4
19. Question
II. 4y2 + 15y + 9 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
y = -3, -3/4
Put all values on number line and analyze the relationship
-3……………-3/4…………3
y = -3, -3/4
Put all values on number line and analyze the relationship
-3……………-3/4…………3
20. Question
II. 4y2 + 23y + 15 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
y = -5, -3/4
Put all values on number line and analyze the relationship
-5……….-3/4…….-3/2………3
y = -5, -3/4
Put all values on number line and analyze the relationship
-5……….-3/4…….-3/2………3
21. Question
Total Quantity of Copper=5/9*18 + 7/9*45=10+35==>45
Ratio=18:45=2:5.
Total Quantity of Copper=5/9*18 + 7/9*45=10+35==>45
Ratio=18:45=2:5.
22. Question
(253/160) * P =1265
P=Rs800.
(253/160) * P =1265
P=Rs800.
23. Question
24. Question
12% of 112 ==>125.44
12% of 125.44 ==> 140.49.
12% of 112 ==>125.44
12% of 125.44 ==> 140.49.
25. Question
27 liter milk and 9 liter water.
Now, 15 liters milk is added then milk becomes 42 liters.
Now, ratio = 42:9 = 14:3.
27 liter milk and 9 liter water.
Now, 15 liters milk is added then milk becomes 42 liters.
Now, ratio = 42:9 = 14:3.
26. Question
27. Question
Weight of new person = (45 + 18) kg = 63 kg.
Weight of new person = (45 + 18) kg = 63 kg.
28. Question
2l + 2b = 5b
3b = 2l
b= (2/3)l
Area = 216
l * b = 216
l * (2/3)l =216
l2= 324
l = 18 cm.
2l + 2b = 5b
3b = 2l
b= (2/3)l
Area = 216
l * b = 216
l * (2/3)l =216
l2= 324
l = 18 cm.
29. Question
Then (3500*12)/7x=2/3
14x=126000
X=Rs 9000.
Then (3500*12)/7x=2/3
14x=126000
X=Rs 9000.
30. Question
Capacity of each bucket =9 liters
Number of buckets needed = 162/9 =18.
Capacity of each bucket =9 liters
Number of buckets needed = 162/9 =18.
31. Question
=120*7=840.
=120*7=840.
32. Question
33. Question
[12000*(16-12)/100] ?==> 100/3=33 1/3%.
[12000*(16-12)/100] ?==> 100/3=33 1/3%.
34. Question
? 16 ==>57.6Deg.
? 16 ==>57.6Deg.
35. Question
The maximum no of passengers are travelling to station Q.
The maximum no of passengers are travelling to station Q.
36. Question
In D = 32 * 7/8 = 28
Required total = 27+28 = 55
In D = 32 * 7/8 = 28
Required total = 27+28 = 55
37. Question
in E, in finance = 48 * 11/6 = 88, so in Others= 360 -(48+88) = 224
Required total = 190 + 224
in E, in finance = 48 * 11/6 = 88, so in Others= 360 -(48+88) = 224
Required total = 190 + 224
38. Question
In C, in Finance = 16 * 5/8 = 10, so males = 80/100 * 10 = 8
In C, in Others = 280 – (16+10) = 254, so males = 50/100 * 254 = 127
Required number = 12+8+127 = 147
In C, in Finance = 16 * 5/8 = 10, so males = 80/100 * 10 = 8
In C, in Others = 280 – (16+10) = 254, so males = 50/100 * 254 = 127
Required number = 12+8+127 = 147
39. Question
40. Question
41. Question
Relative speed =(15+D) +(20-D)=35
Therefore ,time at which they meet with each other = 210/35= 6 hours
Relative speed =(15+D) +(20-D)=35
Therefore ,time at which they meet with each other = 210/35= 6 hours
42. Question
43. Question
Profit = 450 * 40 /100 = 180
If selling price of 600 articles is = Rs. 630
Then the selling priceof one article will be = Rs. 630/600
Selling Price of 630 articles = 630/600 * 630 = Rs. 661.5
Profit = 661.5 – 450 =Rs. 211.5
Profit % = 2115 / 4500 *100 = 47%
Profit = 450 * 40 /100 = 180
If selling price of 600 articles is = Rs. 630
Then the selling priceof one article will be = Rs. 630/600
Selling Price of 630 articles = 630/600 * 630 = Rs. 661.5
Profit = 661.5 – 450 =Rs. 211.5
Profit % = 2115 / 4500 *100 = 47%
44. Question
Amt. of silver in the first silver ring = (4/196+4)* 20 = 0.4 gm
Amt. of gold in the second gold ring = (8/ 8+2)* 10 = 8 gm
Amt. of silver in the second silver ring =(2/ 8+2) *10 = 2 gm
Therefore , ratio of gold : silver = (19.6+8) / (0.4 + 2) = 23/2
Amt. of silver in the first silver ring = (4/196+4)* 20 = 0.4 gm
Amt. of gold in the second gold ring = (8/ 8+2)* 10 = 8 gm
Amt. of silver in the second silver ring =(2/ 8+2) *10 = 2 gm
Therefore , ratio of gold : silver = (19.6+8) / (0.4 + 2) = 23/2
45. Question
= (100 +40)[100-40/100-20] -100
=140(60/80) -100
=105-100
= 5%
= (100 +40)[100-40/100-20] -100
=140(60/80) -100
=105-100
= 5%
46. Question
Now, remaining rest empty positions ie. 6 so we can arrange it in 6 different ways = 6! Ways
Hence , 1* 6! * 1= 720
Now, remaining rest empty positions ie. 6 so we can arrange it in 6 different ways = 6! Ways
Hence , 1* 6! * 1= 720
47. Question
80*10 : 100 * 6 : 120 * 3
800 : 600 : 360
20 : 15 : 9
Therefore , Total rent of the meadow = 400/ 20 *44 =Rs. 880
80*10 : 100 * 6 : 120 * 3
800 : 600 : 360
20 : 15 : 9
Therefore , Total rent of the meadow = 400/ 20 *44 =Rs. 880
48. Question
1 litre in 2 mins.
176 litres -> 176 * 2 = 352 mins.
Remaining 4 litres will be filled in 1 minute = 352 + 1= 353 minutes = 5 hrs 53 mins.
1 litre in 2 mins.
176 litres -> 176 * 2 = 352 mins.
Remaining 4 litres will be filled in 1 minute = 352 + 1= 353 minutes = 5 hrs 53 mins.
49. Question
50. Question
IBPS SO Prelims Quantitative Aptitude Mock Test 2024
Quantitative Aptitude Questions for IBPS SO Prelims Online Test, IBPS SO Free Mock Test Series. IBPS Free Mock Test for IT Officer. The below online test on IBPS Specialist Officer Recruitment will help you for preperation of the post of IT Officer, Agricultural Field Officer, Rajbhasha Adhikari, Law Officer, HR/Personnel Officer, Marketing Officer. IBPS Quantitative Aptitude Online Test in English. IBPS SO Quantitative Aptitude Quiz 2024. The IBPS Full online mock test paper is free for all students. IBPS Mock test for Quantitative Aptitude Subject Via Online Mode. Here we are providing Quantitative Aptitude Question for IBPS SO Exam in English. IBPS SO IT Officer Mock Test Series 2024. Now Test your self for IBPS Exam by using below quiz… This paper has 50 questions. Time allowed is 40 minutes. The IBPS online Mock Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.IBPS SO Prelims Quantitative Aptitude Free Online Mock Test - 1