IPPB Mains Online Test Series 1, IPPB Mains Mock Test Series 1st
Finish Quiz
0 of 50 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
Information
IPPB Mains Online Test Series 1, IPPB Mains Mock Test Series 1st. IPPB Mains Free Mock Test Exam 2024. IPPB Mains Exam Free Online Quiz 2024. IPPB Mains Full Online Mock Test Series 1st in English.candidates who want to make sure whether their preparation level is up to date then they take this online test series without paying anything. CAknowledge provide IPPB Online Test Series 2024 in order to let you excel in the examination. The IPPB Mains Full online mock test paper is free for all students. IPPB Mains Question and Answers in English and Hindi Series 1. Here we are providing IPPB Mains Full Mock Test Paper in English. IPPB Mains Mock Test Series 1st 2024. Now Test your self for IPPB Mains Exam by using below quiz…
This paper has 50 questions.
Time allowed is 50 minutes.
The IPPB Mains Online Test Series 1st, IPPB Mains Free Online Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 50 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
| Average score |
|
| Your score |
|
Categories
- Not categorized 0%
| Pos. | Name | Entered on | Points | Result |
|---|---|---|---|---|
| Table is loading | ||||
| No data available | ||||
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
- Answered
- Review
-
Question 1 of 50
1. Question
A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
Correct
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.Incorrect
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. -
Question 2 of 50
2. Question
What number has a 5:1 ratio to the number 10?
Correct
5:1 = x: 10
x = 50Incorrect
5:1 = x: 10
x = 50 -
Question 3 of 50
3. Question
The average of first 10 even numbers is?
Correct
Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11Incorrect
Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11 -
Question 4 of 50
4. Question
³√?/9261 = 11/21
Correct
?/9261 = (11/21)3 = 1331/9261
=> ? = 1331Incorrect
?/9261 = (11/21)3 = 1331/9261
=> ? = 1331 -
Question 5 of 50
5. Question
An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes?
Correct
Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5
S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25
So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 – 100) = 10.25%.Incorrect
Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5
S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25
So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 – 100) = 10.25%. -
Question 6 of 50
6. Question
Find the area of a parallelogram with base 24 cm and height 16 cm.
Correct
Area of a parallelogram = base * height = 24 * 16 = 384 cm2
Incorrect
Area of a parallelogram = base * height = 24 * 16 = 384 cm2
-
Question 7 of 50
7. Question
The ratio of the cost price and the selling price is 4:5. The profit percent is:
Correct
Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x – 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%.Incorrect
Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x – 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%. -
Question 8 of 50
8. Question
Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?
Correct
Incorrect
-
Question 9 of 50
9. Question
If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 340, the cost of the article is:
Correct
Let C.P. be Rs. x.
Then, 5% of x = 350 – 340 = 10
x/20 = 10 => x = 200Incorrect
Let C.P. be Rs. x.
Then, 5% of x = 350 – 340 = 10
x/20 = 10 => x = 200 -
Question 10 of 50
10. Question
The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is:
Correct
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500Incorrect
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500 -
Question 11 of 50
11. Question
A sum of money lent out at S.I. amounts to Rs. 720 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
Correct
S.I for 5 years = (1020 – 720) = Rs. 300.
S.I. for 2 years = 300/5 * 2 = Rs. 120.
Principal = (720 – 120) = Rs. 600.Incorrect
S.I for 5 years = (1020 – 720) = Rs. 300.
S.I. for 2 years = 300/5 * 2 = Rs. 120.
Principal = (720 – 120) = Rs. 600. -
Question 12 of 50
12. Question
109.13 * 34.14 – 108.12 * 33 = ?
Correct
109 * 34 – 108 * 33
= 3706 – 3564 = 142Incorrect
109 * 34 – 108 * 33
= 3706 – 3564 = 142 -
Question 13 of 50
13. Question
A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man’s rate is?
Correct
DS = 6
US = 4
S = ?
S = (6 – 4)/2 = 1 kmphIncorrect
DS = 6
US = 4
S = ?
S = (6 – 4)/2 = 1 kmph -
Question 14 of 50
14. Question
A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V?
Correct
Incorrect
-
Question 15 of 50
15. Question
Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
Correct
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 – 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.Incorrect
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 – 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec. -
Question 16 of 50
16. Question
The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
Correct
D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m.Incorrect
D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m. -
Question 17 of 50
17. Question
Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
Correct
Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 ——– 7
4 ——— ? → 28 mIncorrect
Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 ——– 7
4 ——— ? → 28 m -
Question 18 of 50
18. Question
A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Correct
Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 secIncorrect
Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec -
Question 19 of 50
19. Question
Find the one which does not belong to that group ?
Correct
Walk, Talk, Drink and Lick are verbs, but not Plank.
Incorrect
Walk, Talk, Drink and Lick are verbs, but not Plank.
-
Question 20 of 50
20. Question
Which one of the following is the least number of four digits divisible by 71?
Correct
1000/71 = 14 6/71
1000 + 71 – 6 = 1065Incorrect
1000/71 = 14 6/71
1000 + 71 – 6 = 1065 -
Question 21 of 50
21. Question
The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is?
Correct
Incorrect
-
Question 22 of 50
22. Question
The length of each side of an equilateral triangle having an area of 4√3 cm2 is?
Correct
√3/4a2 = 4√3 → a = 4
Incorrect
√3/4a2 = 4√3 → a = 4
-
Question 23 of 50
23. Question
3251 + 587 + 369 – ? = 3007
Correct
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200Incorrect
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200 -
Question 24 of 50
24. Question
A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
Correct
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50
Incorrect
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50
-
Question 25 of 50
25. Question
A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in?
Correct
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days.Incorrect
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days. -
Question 26 of 50
26. Question
A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?
Correct
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%.Incorrect
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%. -
Question 27 of 50
27. Question
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
Correct
Relative speed = (40 – 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.Incorrect
Relative speed = (40 – 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m. -
Question 28 of 50
28. Question
If 70% of an equal to 40% of b, then ratio between a and b is?
Correct
70 a = 40 b
a: b = 4: 7Incorrect
70 a = 40 b
a: b = 4: 7 -
Question 29 of 50
29. Question
If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are?
Correct
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750Incorrect
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750 -
Question 30 of 50
30. Question
A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
Correct
x ——- 9
(x + 10) —- 6
x * 9 = (x + 10)6
x = 20Incorrect
x ——- 9
(x + 10) —- 6
x * 9 = (x + 10)6
x = 20 -
Question 31 of 50
31. Question
The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Correct
Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X – 48 = 180
1000/x – 48 * 5/18 = 180
50 = 9X – 120
X = 68 KmphIncorrect
Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X – 48 = 180
1000/x – 48 * 5/18 = 180
50 = 9X – 120
X = 68 Kmph -
Question 32 of 50
32. Question
Find the roots of the quadratic equation: 2x2 + 3x – 9 = 0?
Correct
2x2 + 6x – 3x – 9 = 0
2x(x + 3) – 3(x + 3) = 0
(x + 3)(2x – 3) = 0
=> x = -3 or x = 3/2.Incorrect
2x2 + 6x – 3x – 9 = 0
2x(x + 3) – 3(x + 3) = 0
(x + 3)(2x – 3) = 0
=> x = -3 or x = 3/2. -
Question 33 of 50
33. Question
A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Correct
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.Incorrect
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m. -
Question 34 of 50
34. Question
A man buys an article for 10% less than its value and sells it for 10% more than its value. His gain or loss percent is:
Correct
Let the article be worth Rs. x.
C.P. 90% of Rs. x = Rs. 9x/10
S.P. = 110% of Rs. x = Rs. 11x/10
Gain = (11x/10 – 9x/10) = Rs. x/5
Gain % = x/5 * 10/9x * 100 = 22 2/9 % > 20%Incorrect
Let the article be worth Rs. x.
C.P. 90% of Rs. x = Rs. 9x/10
S.P. = 110% of Rs. x = Rs. 11x/10
Gain = (11x/10 – 9x/10) = Rs. x/5
Gain % = x/5 * 10/9x * 100 = 22 2/9 % > 20% -
Question 35 of 50
35. Question
In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Correct
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m.Incorrect
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m. -
Question 36 of 50
36. Question
In a two-digit number, if it is known that its unit’s digit exceeds its ten’s digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
Correct
Let the ten’s digit be x. Then, unit’s digit = x + 2. Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2
(11x + 2)(2x + 2) = 144
2×2 + 26x – 140 = 0
(x – 2)(11x + 35) = 0
x = 2
Hence, required number = 11x + 2 = 24.Incorrect
Let the ten’s digit be x. Then, unit’s digit = x + 2. Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2
(11x + 2)(2x + 2) = 144
2×2 + 26x – 140 = 0
(x – 2)(11x + 35) = 0
x = 2
Hence, required number = 11x + 2 = 24. -
Question 37 of 50
37. Question
How much 60% of 50 is greater than 40% of 30?
Correct
(60/100) * 50 – (40/100) * 30
30 – 12 = 18Incorrect
(60/100) * 50 – (40/100) * 30
30 – 12 = 18 -
Question 38 of 50
38. Question
How many figures are required to number the pages the pages of a book containing 365 pages?
Correct
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987Incorrect
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987 -
Question 39 of 50
39. Question
A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Correct
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 secIncorrect
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec -
Question 40 of 50
40. Question
A man gains 20% by selling an article for a certain price. If the sells it at double the price, the percentage of profit will be:
Correct
Let C.P. = Rs. x.
Then, S.P. = Rs. (12% of x) = Rs. 6x/5
New S.P. = 2 * 6x/5 = Rs. 12x/5
Profit = 12x/5 – x = Rs. 7x/5
Profit = 7x/5 * 1/x * 100 = 140%.Incorrect
Let C.P. = Rs. x.
Then, S.P. = Rs. (12% of x) = Rs. 6x/5
New S.P. = 2 * 6x/5 = Rs. 12x/5
Profit = 12x/5 – x = Rs. 7x/5
Profit = 7x/5 * 1/x * 100 = 140%. -
Question 41 of 50
41. Question
A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
Correct
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20.Incorrect
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20. -
Question 42 of 50
42. Question
In an examination 40% failed in Hindi, 45% failed in English. If 25% students failed in both the subjects. Then the percentage of failed students is?
Correct
Incorrect
-
Question 43 of 50
43. Question
25% of 30% of 45% is equal to?
Correct
(25/100) * (30/100) * (45/100)
1/4 * 3/10 * 9/20
27/800 = 0.03375Incorrect
(25/100) * (30/100) * (45/100)
1/4 * 3/10 * 9/20
27/800 = 0.03375 -
Question 44 of 50
44. Question
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
Correct
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4Incorrect
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4 -
Question 45 of 50
45. Question
In a 1000 m race, A beats B by 50 m and B beats C by 100 m. In the same race, by how many meters does A beat C?
Correct
By the time A covers 1000 m, B covers (1000 – 50) = 950 m.
By the time B covers 1000 m, C covers (1000 – 100) = 900 m.
So, the ratio of speeds of A and C =
1000/950 * 1000/900 = 1000/855 So, by the time A covers 1000 m, C covers 855 m.
So in 1000 m race A beats C by 1000 – 855 = 145 m.Incorrect
By the time A covers 1000 m, B covers (1000 – 50) = 950 m.
By the time B covers 1000 m, C covers (1000 – 100) = 900 m.
So, the ratio of speeds of A and C =
1000/950 * 1000/900 = 1000/855 So, by the time A covers 1000 m, C covers 855 m.
So in 1000 m race A beats C by 1000 – 855 = 145 m. -
Question 46 of 50
46. Question
An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?
Correct
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3Incorrect
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3 -
Question 47 of 50
47. Question
In a class there are 20 boys and 25 girls. In how many ways can a boy and a girl be selected?
Correct
We can select one boy from 20 boys in 20 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 20 * 25 ways i.e., = 500 ways.Incorrect
We can select one boy from 20 boys in 20 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 20 * 25 ways i.e., = 500 ways. -
Question 48 of 50
48. Question
A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?
Correct
The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000Incorrect
The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000 -
Question 49 of 50
49. Question
A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
Correct
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000Incorrect
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000 -
Question 50 of 50
50. Question
A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is:
Correct
Let the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.
125/100 * 120/100 * 118/100 * x = 3009/100
177/100 x = 3009/100 => x = 17Incorrect
Let the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.
125/100 * 120/100 * 118/100 * x = 3009/100
177/100 x = 3009/100 => x = 17
