IPPB Mains Test Series 3, IPPB Mains mock test, IPPB Online Test
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IPPB Mains Test Series 3, IPPB Mains mock test, IPPB Online Test 2024, IPPB Mains Free Mock Test Exam 2024. IPPB Mains Exam Free Online Quiz 2024. IPPB Mains Full Online Mock Test Series 3rd in English. We will provide you with free mock tests and 3 sectional tests just to improvise your hold on selective subjects or topics. This IPPB online test series is based on updated syllabus and pattern. The IPPB Mains Full online mock test paper is free for all students. IPPB Mains Question and Answers in English and Hindi Series 3. Here we are providing IPPB Mains Full Mock Test Paper in English. IPPB Mains Mock Test Series 3rd 2024. Now Test your self for IPPB Mains Exam by using below quiz…
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Question 1 of 50
1. Question
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Correct
Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Incorrect
Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
-
Question 2 of 50
2. Question
A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Correct
100 — 10 DS = 10
? —- 1
75 —- 15 US = 5
? —– 1 S = (10 – 5)/2
= 2 2 ½ kmphIncorrect
100 — 10 DS = 10
? —- 1
75 —- 15 US = 5
? —– 1 S = (10 – 5)/2
= 2 2 ½ kmph -
Question 3 of 50
3. Question
The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
Correct
15 CP = 18 SP
18 — 3 CP loss
100 — ? => 16 2/3% lossIncorrect
15 CP = 18 SP
18 — 3 CP loss
100 — ? => 16 2/3% loss -
Question 4 of 50
4. Question
20 women can do a work in 9 days. After they have worked for 6 days. 6 more men join them. How many days will they take to complete the remaining work?
Correct
(20 * 16) women can complete the work in 1 day.
1 woman’s 1 day work = 1/320
(16 * 15) men can complete the work in 1 day
1 man’s 1 day work = 1/240
So, required ratio = 1/240 : 1/320 = 4:3.Incorrect
(20 * 16) women can complete the work in 1 day.
1 woman’s 1 day work = 1/320
(16 * 15) men can complete the work in 1 day
1 man’s 1 day work = 1/240
So, required ratio = 1/240 : 1/320 = 4:3. -
Question 5 of 50
5. Question
The difference between the two digit number and the number obtained by interchanging its digits is 54. The difference between the digits is?
Correct
(10x + y) – (10y + x) = 54
x – y = 6Incorrect
(10x + y) – (10y + x) = 54
x – y = 6 -
Question 6 of 50
6. Question
Anil invested a sum of money at a certain rate of simple interest for a period of five years. Had he invested the sum for a period of eight years for the same rate, the total intrest earned by him would have been sixty percent more than the earlier interest amount. Find the rate of interest p.a.
Correct
Let the sum be Rs.P. Let the rate of interest be R% p.a.
(P)(8)(R)/100 = [1 + 6/100][ (P)(5)(R) /100] = 1.6{5PR/100]
8PR/100 = 8PR/100 which is anyway true.
R cannot be found.Incorrect
Let the sum be Rs.P. Let the rate of interest be R% p.a.
(P)(8)(R)/100 = [1 + 6/100][ (P)(5)(R) /100] = 1.6{5PR/100]
8PR/100 = 8PR/100 which is anyway true.
R cannot be found. -
Question 7 of 50
7. Question
Three 6 faced dice are thrown together. The probability that all the three show the same number on them is -.
Correct
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36Incorrect
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36 -
Question 8 of 50
8. Question
The product of two successive numbers is 4556. Which of the following is the larger of the two numbers?
Correct
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n2 + n – 4556 = 0
=> n2 + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68.Incorrect
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n2 + n – 4556 = 0
=> n2 + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68. -
Question 9 of 50
9. Question
A man walked 20 m to cross a rectangular field diagonally. If the length of the field is 16 cm. Find the breadth of the field is?
Correct
Incorrect
-
Question 10 of 50
10. Question
The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years. Tee age of the 15th student is:
Correct
Age of the 15th student=
[15 * 15 – (14 * 5 + 16 * 9)] = (225 – 214) = 11 years.Incorrect
Age of the 15th student=
[15 * 15 – (14 * 5 + 16 * 9)] = (225 – 214) = 11 years. -
Question 11 of 50
11. Question
Find the ratio between whole surfaces of a sphere and a hemisphere?
Correct
4 πr2 : 3 πr2 => 4:3
Incorrect
4 πr2 : 3 πr2 => 4:3
-
Question 12 of 50
12. Question
A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in?
Correct
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days.Incorrect
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days. -
Question 13 of 50
13. Question
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill cistern. How much time will be taken by A to fill the cistern separately?
Correct
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
1/x + 1/(x + 6) = 1/4
x2 – 2x – 24 = 0
(x – 6)(x + 4) = 0 => x = 6.Incorrect
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
1/x + 1/(x + 6) = 1/4
x2 – 2x – 24 = 0
(x – 6)(x + 4) = 0 => x = 6. -
Question 14 of 50
14. Question
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is?
Correct
Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 – 100) = 6.09%
Incorrect
Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 – 100) = 6.09%
-
Question 15 of 50
15. Question
What is the sum of the local values of the digits 2, 3, 4, 5 in the number 2345?
Correct
2000 + 300 + 40 + 5 = 2345
Incorrect
2000 + 300 + 40 + 5 = 2345
-
Question 16 of 50
16. Question
A rectangular field 30 m long and 20 m broad. How much deep it should be dug so that from the earth taken out, a platform can be formed which is 8 m long, 5.5 m broad and 1.5 m high where as the earth taken out is increase by 10/5?
Correct
30 * 20 * x = (8 * 5.5 * 1.5)/2
Incorrect
30 * 20 * x = (8 * 5.5 * 1.5)/2
-
Question 17 of 50
17. Question
Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
Correct
4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120Incorrect
4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120 -
Question 18 of 50
18. Question
Subtracting 10% from X is the same as multiplying X by what number?
Correct
X – (10/100) X = X * ?
? = 90%Incorrect
X – (10/100) X = X * ?
? = 90% -
Question 19 of 50
19. Question
Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Correct
Distance covered by Amar = 18/4.8 (1.6km) = 3/8(1600) = 600 m
Incorrect
Distance covered by Amar = 18/4.8 (1.6km) = 3/8(1600) = 600 m
-
Question 20 of 50
20. Question
Tanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. Eight years ago, what was the ratio of Tanya’s age to that of her grandfather?
Correct
16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.
8x + 24 = 3(x + 24) => 5x = 48
8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53Incorrect
16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.
8x + 24 = 3(x + 24) => 5x = 48
8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53 -
Question 21 of 50
21. Question
The product of two numbers is 2025 and their HCF is 15 their LCM is:
Correct
Incorrect
-
Question 22 of 50
22. Question
The third proportional to 1 and 2 is?
Correct
(2*2)/1 = 4
Incorrect
(2*2)/1 = 4
-
Question 23 of 50
23. Question
If 4 2/3 is subtracted form 10 1/2 and the difference is multiplied by 450, then what is the final answer?
Correct
Final answer = (10 1/2 – 4 2/3) * 450
= 5 5/6 * 450 = 5 * 450 + 5/6 * 450
= 2250 + 375 = 2625.Incorrect
Final answer = (10 1/2 – 4 2/3) * 450
= 5 5/6 * 450 = 5 * 450 + 5/6 * 450
= 2250 + 375 = 2625. -
Question 24 of 50
24. Question
P is three times as fast as Q and working together, they can complete a work in 12 days. In how many days can Q alone complete the work?
Correct
P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 12 days, which means Q can do the work in 48 days.
Hence, P can do the work in 16 days.Incorrect
P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 12 days, which means Q can do the work in 48 days.
Hence, P can do the work in 16 days. -
Question 25 of 50
25. Question
6 – [5/6 + {3 7/8 – 2 1/3 + 1 7/9}] = ?
Correct
6 – [5/6 + {3 7/8 – 2 1/3} + 1 7/9] => 6 – [5/6 + {3 1/8 – 7/3} + 16/9]
=> 6 – [5/6 + {(279 – 168 + 128)/72}] => 6 – 5/6 + 239/72
=> 6 – (60 + 239)/72 => 6 – 46 – 11/72
=> 2 – 11/72 => 1 + 1 – 11/72 => 1 + 61/72 = 1 61/72Incorrect
6 – [5/6 + {3 7/8 – 2 1/3} + 1 7/9] => 6 – [5/6 + {3 1/8 – 7/3} + 16/9]
=> 6 – [5/6 + {(279 – 168 + 128)/72}] => 6 – 5/6 + 239/72
=> 6 – (60 + 239)/72 => 6 – 46 – 11/72
=> 2 – 11/72 => 1 + 1 – 11/72 => 1 + 61/72 = 1 61/72 -
Question 26 of 50
26. Question
125 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4?
Correct
Milk = 3/5 * 125 = 75 liters
Water = 50 liters
75 : (50+P) = 3:4
150 + 3P = 400 => P = 50
50 liters of water are to be added for the ratio become 3:4.Incorrect
Milk = 3/5 * 125 = 75 liters
Water = 50 liters
75 : (50+P) = 3:4
150 + 3P = 400 => P = 50
50 liters of water are to be added for the ratio become 3:4. -
Question 27 of 50
27. Question
In an examination a pupil’s average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?
Correct
Let the number of papers be x. Then,
63x + 20 + 2 = 65x
= 2x = 22
= x = 11.Incorrect
Let the number of papers be x. Then,
63x + 20 + 2 = 65x
= 2x = 22
= x = 11. -
Question 28 of 50
28. Question
The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?
Correct
X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000Incorrect
X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000 -
Question 29 of 50
29. Question
Find the smallest number which should be multiplied with 520 to make it a perfect square.
Correct
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.Incorrect
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square. -
Question 30 of 50
30. Question
The average of 35 numbers is 25. If each number is multiplied by 5, find the new average?
Correct
Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125.Incorrect
Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125. -
Question 31 of 50
31. Question
Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?
Correct
1/30 + 1/40 = 7/120
120/7 = 17 1/7 daysIncorrect
1/30 + 1/40 = 7/120
120/7 = 17 1/7 days -
Question 32 of 50
32. Question
A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?
Correct
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days.Incorrect
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days. -
Question 33 of 50
33. Question
In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
Correct
100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400Incorrect
100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400 -
Question 34 of 50
34. Question
Find the roots of quadratic equation: 2x2 + 5x + 2 = 0?
Correct
2x2 + 4x + x + 2 = 0
2x(x + 2) + 1(x + 2) = 0
(x + 2)(2x + 1) = 0 => x = -2, -1/2Incorrect
2x2 + 4x + x + 2 = 0
2x(x + 2) + 1(x + 2) = 0
(x + 2)(2x + 1) = 0 => x = -2, -1/2 -
Question 35 of 50
35. Question
The sum of two numbers is 25 and their difference is 13. Find their product.
Correct
Let the numbers be x and y.
Then x + y = 25 and x – y = 13.
x = 19; y = 6
xy = 19 * 6 = 114Incorrect
Let the numbers be x and y.
Then x + y = 25 and x – y = 13.
x = 19; y = 6
xy = 19 * 6 = 114 -
Question 36 of 50
36. Question
6.4 * 1.25 = (?)3
Correct
8 = (?)3
=> ?3 = 23 => ? = 2Incorrect
8 = (?)3
=> ?3 = 23 => ? = 2 -
Question 37 of 50
37. Question
The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
Correct
π * 12 * 4 = 48
Incorrect
π * 12 * 4 = 48
-
Question 38 of 50
38. Question
A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Correct
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.Incorrect
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m. -
Question 39 of 50
39. Question
Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
Correct
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b.Incorrect
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b. -
Question 40 of 50
40. Question
If y3 = 0.008, y5 = ?
Correct
y = 3√0.008 = 0.2
y5 = (0.2)5 = 0.00032.Incorrect
y = 3√0.008 = 0.2
y5 = (0.2)5 = 0.00032. -
Question 41 of 50
41. Question
A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
Correct
S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 minIncorrect
S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 min -
Question 42 of 50
42. Question
A can do a job in 18 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ——- days?
Correct
1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ daysIncorrect
1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ days -
Question 43 of 50
43. Question
If 34m+1 = 37m-5, solve for m.
Correct
34m+1 = 37m-5 equating powers of 3 on both sides, 4m+1 = 7m – 5 => 3m = 6 => m = 2.
Incorrect
34m+1 = 37m-5 equating powers of 3 on both sides, 4m+1 = 7m – 5 => 3m = 6 => m = 2.
-
Question 44 of 50
44. Question
The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.
Correct
S = (1 + 2 + 3)/2 = 3
=> No triangle existsIncorrect
S = (1 + 2 + 3)/2 = 3
=> No triangle exists -
Question 45 of 50
45. Question
A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Correct
Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmphIncorrect
Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmph -
Question 46 of 50
46. Question
A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
Correct
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.Incorrect
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days. -
Question 47 of 50
47. Question
The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
Correct
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5Incorrect
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5 -
Question 48 of 50
48. Question
Find the one which does not belong to that group ?
Correct
Except Regiment, all others are caders of army officers.
Incorrect
Except Regiment, all others are caders of army officers.
-
Question 49 of 50
49. Question
Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
Correct
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60Incorrect
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60 -
Question 50 of 50
50. Question
The length of a rectangle is two – fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Correct
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.unitsIncorrect
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
