IPPB Pre Online Test Series 5, IPPB Prelims Mock Test Series 5th
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IPPB Pre Online Test Series 5, IPPB Prelims Mock Test Series 5th, IPPB Prelims Free Mock Test Exam 2024. IPPB Prelims Exam Free Online Quiz 2024. IPPB Prelims Full Online Mock Test Series 5th in English.candidates who want to make sure whether their preparation level is up to date then they take this online test series without paying anything. CAknowledge provide IPPB Online Test Series 2024 in order to let you excel in the examination. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi Series 5. Here we are providing IPPB Prelims Full Mock Test Paper in English. IPPB Prelims Mock Test Series 5th 2024. Now Test your self for IPPB Prelims Exam by using below quiz…
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Question 1 of 50
1. Question
Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?
Correct
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48.Incorrect
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48. -
Question 2 of 50
2. Question
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Correct
Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.
Incorrect
Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.
-
Question 3 of 50
3. Question
A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most -.
Correct
Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 216 – 1 = 215.Incorrect
Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 216 – 1 = 215. -
Question 4 of 50
4. Question
Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Correct
x + y = 80
x – 4y = 5
x = 65 y = 15Incorrect
x + y = 80
x – 4y = 5
x = 65 y = 15 -
Question 5 of 50
5. Question
The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
Correct
Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x – 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 – 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2Incorrect
Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x – 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 – 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2 -
Question 6 of 50
6. Question
A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?
Correct
20 15 5
25 20 8
500 + 300 + 40 = 840/40 = 21Incorrect
20 15 5
25 20 8
500 + 300 + 40 = 840/40 = 21 -
Question 7 of 50
7. Question
Find the number which multiplied by 15 is increased by 196.
Correct
Let the number be x. Then,
15x – x = 196
x = 14Incorrect
Let the number be x. Then,
15x – x = 196
x = 14 -
Question 8 of 50
8. Question
If the arithmetic mean of seventy five numbers is calculated, it is 35. If each number is increased by 5, then mean of new number is:
Correct
A.M. of 75 numbers = 35
Sum of 75 numbers = 75 * 35 = 2625
Total increase = 75 * 5 = 375
Increased sum = 2625 + 375 = 3000
Increased average = 3000/75 = 40.Incorrect
A.M. of 75 numbers = 35
Sum of 75 numbers = 75 * 35 = 2625
Total increase = 75 * 5 = 375
Increased sum = 2625 + 375 = 3000
Increased average = 3000/75 = 40. -
Question 9 of 50
9. Question
25 2/5 + 8 4/5 + 4/5 = ?
Correct
25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35
Incorrect
25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35
-
Question 10 of 50
10. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 daysIncorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days -
Question 11 of 50
11. Question
(64 + 9 + 9) / (2 * 20 + 1) = ?
Correct
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2
Incorrect
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2
-
Question 12 of 50
12. Question
108 * 107 * 96 = ? (to the nearest hundred)
Correct
108 * 107 * 96 ≡ 1109400
Incorrect
108 * 107 * 96 ≡ 1109400
-
Question 13 of 50
13. Question
The area of a base of a cone is 30 cm2. If the height of the cone is 6cm, find its volume?
Correct
πr2 = 30 h = 6
1/3 * 30 * 6 = 60Incorrect
πr2 = 30 h = 6
1/3 * 30 * 6 = 60 -
Question 14 of 50
14. Question
The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:
Correct
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.Incorrect
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs. -
Question 15 of 50
15. Question
Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit?
Correct
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30.Incorrect
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30. -
Question 16 of 50
16. Question
(1.9 * 0.021) / (0.095 * 0.105) = ?
Correct
(1.9 * 0.021) / (0.095 * 0.105) = (19 * 21 * 100) / (95 * 105) = 4.
Incorrect
(1.9 * 0.021) / (0.095 * 0.105) = (19 * 21 * 100) / (95 * 105) = 4.
-
Question 17 of 50
17. Question
A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?
Correct
2/7 – 1/x = 1/4
x = 28Incorrect
2/7 – 1/x = 1/4
x = 28 -
Question 18 of 50
18. Question
Find the least number by which (59)(36)(17) has to be multiplied to obtain a perfect square?
Correct
For any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.
The least number = (5)(17) = 85.Incorrect
For any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.
The least number = (5)(17) = 85. -
Question 19 of 50
19. Question
What is the least number to be subtracted from 11, 15, 21 and 30 each so that the resultant numbers become proportional?
Correct
Let the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.
<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x)Incorrect
Let the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.
<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x) -
Question 20 of 50
20. Question
In how many ways can three consonants and two vowels be selected from the letters of the word “TRIANGLE”?
Correct
The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.Incorrect
The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways. -
Question 21 of 50
21. Question
Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
Correct
Work done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40
Volume of 1/40 part = 3 gallons\
Volume of whole = 3 * 40 = 120 gallons.Incorrect
Work done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40
Volume of 1/40 part = 3 gallons\
Volume of whole = 3 * 40 = 120 gallons. -
Question 22 of 50
22. Question
If the sum and difference of two numbers are 20 and 8 respectively, then the difference of their square is:
Correct
Let the numbers be x and y.
Then, x + y = 20 and x – y = 8
x2 – y2 = (x + y)(x – y) = 20 * 8 = 160.Incorrect
Let the numbers be x and y.
Then, x + y = 20 and x – y = 8
x2 – y2 = (x + y)(x – y) = 20 * 8 = 160. -
Question 23 of 50
23. Question
In a partnership between A, B and C. A’s capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C’s share is Rs.130, what is B’s capital?
Correct
200 + 130 = 330
800 – 330 = 470
200 —- 5000
470 —- ? => 11750Incorrect
200 + 130 = 330
800 – 330 = 470
200 —- 5000
470 —- ? => 11750 -
Question 24 of 50
24. Question
25 * 25 / 25 + 15 * 40 = ?
Correct
(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.
Incorrect
(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.
-
Question 25 of 50
25. Question
The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Correct
Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.Incorrect
Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years. -
Question 26 of 50
26. Question
Which of the following number is divisible by 4 and 9?
Correct
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9.Incorrect
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9. -
Question 27 of 50
27. Question
A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after one year service. He served only for 9 months and received uniform and Rs.650, find the price of the uniform?
Correct
9/12 = 3/4 * 900 = 675
= 650
= ————-
= 25
1/4 ——– 25
1 ——— ? => Rs.100Incorrect
9/12 = 3/4 * 900 = 675
= 650
= ————-
= 25
1/4 ——– 25
1 ——— ? => Rs.100 -
Question 28 of 50
28. Question
How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
Correct
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
Incorrect
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
-
Question 29 of 50
29. Question
What percentage of numbers from 1 to 70 have squares that end in the digit 1?
Correct
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such numbers = 14.
Required percentage = (14/70 * 100) = 20%
Learn more problems on : PercentagesIncorrect
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such numbers = 14.
Required percentage = (14/70 * 100) = 20%
Learn more problems on : Percentages -
Question 30 of 50
30. Question
A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
Correct
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20.Incorrect
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20. -
Question 31 of 50
31. Question
109.13 * 34.14 – 108.12 * 33 = ?
Correct
109 * 34 – 108 * 33
= 3706 – 3564 = 142Incorrect
109 * 34 – 108 * 33
= 3706 – 3564 = 142 -
Question 32 of 50
32. Question
12 3/4 * (1 2/17 / 8 1/6) / 5 4/3 = ?
Correct
By applying BODMAS rule.
51/4 * (19/17 / 49/6) / 19/3
= 51/4 * ( 19/17 * 6/49) * 3/19 = 27/98Incorrect
By applying BODMAS rule.
51/4 * (19/17 / 49/6) / 19/3
= 51/4 * ( 19/17 * 6/49) * 3/19 = 27/98 -
Question 33 of 50
33. Question
A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?
Correct
P —- 2P —- 8 years
2 1/4 P —- 10 yearsIncorrect
P —- 2P —- 8 years
2 1/4 P —- 10 years -
Question 34 of 50
34. Question
The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?
Correct
100 —- 300 — 3
900 — 3
—-
6 yearsIncorrect
100 —- 300 — 3
900 — 3
—-
6 years -
Question 35 of 50
35. Question
Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
Correct
I = (500*9*6)/100 = 270
Incorrect
I = (500*9*6)/100 = 270
-
Question 36 of 50
36. Question
A starts business with a capital of Rs.1200 B and C join with some investments after 3 and 6 months respectively. If the end of a year, the profit is divided in the ratio 2:3:5 respectively. What is B’s investment in the business?
Correct
1200 * 12: x * 9 = 2:3
x = 2400Incorrect
1200 * 12: x * 9 = 2:3
x = 2400 -
Question 37 of 50
37. Question
Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.
Correct
Using question number 11 and 12, we get the probability as
1 – (1/36 + 5/9) = 5/12Incorrect
Using question number 11 and 12, we get the probability as
1 – (1/36 + 5/9) = 5/12 -
Question 38 of 50
38. Question
Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
Correct
Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours.Incorrect
Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours. -
Question 39 of 50
39. Question
Ravi invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Ravi’s investments if the interests from those investments are equal?
Correct
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6Incorrect
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6 -
Question 40 of 50
40. Question
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Correct
Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 => x = 50 km/hr.Incorrect
Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 => x = 50 km/hr. -
Question 41 of 50
41. Question
A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?
Correct
30% ———— 50
45% ———— 25
———————-
15% ————- 75
30% ————– ?
150 + 50 = 200 MarksIncorrect
30% ———— 50
45% ———— 25
———————-
15% ————- 75
30% ————– ?
150 + 50 = 200 Marks -
Question 42 of 50
42. Question
The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
Correct
10 CP = 12 SP
12 — 2 CP loss
100 — ? => 16 2/3%Incorrect
10 CP = 12 SP
12 — 2 CP loss
100 — ? => 16 2/3% -
Question 43 of 50
43. Question
Two third of three- fifth of one fourth of a number is 24, what is 30% of that number?
Correct
x * 2/3 * 3/5 * 1/4 = 24
x = 240
240 * 30/100 = 72Incorrect
x * 2/3 * 3/5 * 1/4 = 24
x = 240
240 * 30/100 = 72 -
Question 44 of 50
44. Question
The sector of a circle has radius of 21 cm and central angle 135o. Find its perimeter?
Correct
Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 21) + 2(21)
= 49.5 + 42 = 91.5 cmIncorrect
Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 21) + 2(21)
= 49.5 + 42 = 91.5 cm -
Question 45 of 50
45. Question
In what time a sum of money double itself at 3% per annum simple interest?
Correct
P = (P*3*R)/100
R = 33 1/3%Incorrect
P = (P*3*R)/100
R = 33 1/3% -
Question 46 of 50
46. Question
The simple form of the ratio 2/3:2/5 is?
Correct
2/3 : 2/5 = 10:6 = 5:3
Incorrect
2/3 : 2/5 = 10:6 = 5:3
-
Question 47 of 50
47. Question
If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :
Correct
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22Incorrect
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22 -
Question 48 of 50
48. Question
Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings.
Correct
Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income – expenditure = 5x – 4x = x
So, savings = Rs. 3600.Incorrect
Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income – expenditure = 5x – 4x = x
So, savings = Rs. 3600. -
Question 49 of 50
49. Question
The ratio between the school ages of Neelam and Shaan is 5:6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age of 5:9, then what is the school age of Shaan?
Correct
Let the school ages of Neelam and Shaan be 5x and 6x years respectively.
Then, (1/3 * 5x)/(1/2 * 6x) = 5/9
15 = 15
Thus, Shaan’s age cannot be determined.Incorrect
Let the school ages of Neelam and Shaan be 5x and 6x years respectively.
Then, (1/3 * 5x)/(1/2 * 6x) = 5/9
15 = 15
Thus, Shaan’s age cannot be determined. -
Question 50 of 50
50. Question
A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself?
Correct
100 —- 200 —- 4
400 —- 4
800 —- 4
——
12 yearsIncorrect
100 —- 200 —- 4
400 —- 4
800 —- 4
——
12 years